Solution Manual for Beginning and Intermediate Algebra, 5th Edition

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SOLUTIONSMANUALBEGINNING ANDINTERMEDIATEALGEBRAFIFTHEDITIONJohn TobeyNorth Shore Community CollegeDanvers, MassachusettsJeffrey SlaterNorth Shore Community CollegeDanvers, MassachusettsJamie BlairOrange Coast CollegeCosta Mesa, CaliforniaJennifer CrawfordNormandale Community CollegeBloomington, Minnesota

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ContentsChapter 01Chapter 118Chapter 237Chapter 374Chapter 4109Chapter 5140Chapter 6162Chapter 7185Chapter 8214Chapter 9240Chapter 10289Chapter 11317Chapter 12339Practice Final Examination364

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1Chapter 00.1 Exercises2.13 :1717 is the denominator4.1:317or3176.33 48.205452446×==6×10.818148686×==×12.72184418181×==×14.323211643222×==×16.331133551155×==×18.6397781999×==×20.==31945 1935515422.75457 54777495==24.==64156 4166636526.82513 25833241==28.117927 79117770972==30.15124418 1241515882844404===32.×++===2(45)2202224 555534.×++===1(512)16016151212121236.5(16)565111 6666×++===38.2(63)2182206 3333×++===40.1(109)19019110 9999×++===42.787866=÷136 7861818078136=

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra244.×=⇒=×5?5630954965446.×=⇒=×5?5525945954548.×=⇒=×13?1333917511735150.10?10440156015460×=⇒=×52.7?75358408540×=⇒=×54.45?4529050100502100×=⇒=×56.205454241064106×==×58.1400702070242012120121×==×60.=++33 is raisins131562.+=++1341315does not contain nuts64.663236814727×===+×37of the students enrolled in 1994 were male.Classroom Quiz 0.11.567878811811×==×2.11(514)11701181514141414×++⇒==3.109191212=912 10910810.2 Exercises2.You must change the fractions to equivalentfractions with a common denominator.4.2117and302030 = 2⋅3⋅520 = 2⋅2⋅5LCD = 2⋅2⋅3⋅5 = 606.51and182418 = 2⋅3⋅324 = 2⋅2⋅2⋅3LCD = 2⋅2⋅2⋅3⋅3 = 728.57and164816 = 2⋅2⋅2⋅248 = 2⋅2⋅2⋅2⋅3LCD = 2⋅2⋅2⋅2⋅3 = 4810.117and122012 = 2⋅2⋅320 = 2⋅2⋅5LCD = 2⋅2⋅3⋅5 = 6012.78and304530 = 2⋅3⋅545 = 3⋅3⋅5LCD = 2⋅3⋅3⋅5 = 9014.139,, and714357 = 714 = 2⋅735 = 5⋅7LCD = 2⋅5⋅7 = 7016.3511,, and812428 = 2⋅2⋅212 = 2⋅2⋅342 = 2⋅3⋅7LCD = 2⋅2⋅2⋅3⋅7 = 168

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ISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review318.5311,and814168 = 2⋅2⋅214 = 2⋅716 = 2⋅2⋅2⋅2LCD = 2⋅2⋅2⋅2⋅7 = 11220.3535811111111++==22.11211293151515155−−===24.31333134952611or 1201520315460606060××+=+=+=××26.434735281513575775353535××−=−=−=××28.3133189817838338242424××+=+=+=××30.27227342125515101521033030306××+=+=+==××32.212321223422319122412224242424×−=−=−=×34.131131313310215515531515153×−=−=−==×36.75795463208311or 249499436363636××+=+=+=××38.47136492110643or 17936363636363++=++=40.134173644121421127146214718168484844184×××++=++×××=++=42.1211132511531553351531011151515215××+−=+−××=+−=44.+−=+−==53159861248324242424446.+=+=+==1125137552127732586862424242448.+=+=+==232038098956734341212121250.−=−=−==23371514875731373354542020202052.831131311339741472415515515151515−=−=−==54.+=+=+==11221366911571034773732121212156.1237172021256333333−=−==58.12112911824799191313131313+=+==60.+=+==193199281430103030301562.2217378511119615713353515151515+=+=+==64.−=−==15315961248242424466.1119177651251642343412121212−=−=−==68.313632614526810810181510444040771401119 40−=−=−==70.255530535171131831818181818+=+=+==

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra472.32313215512828337614454520202020+=+=+==74.52829224291953283248188888−=−=−==76.112212156105182432431266322412121241312534 12++=++=++==They ran a total of53412 miles.78.31271581712443443213153212121219612416 12116 3+−=+−=+−===There are now116 3 gallons.80.5937737473144inch816816161616−=−=−=It is smaller so it will slide in and out easily.82.11514014192221621616161616+=+=+==The fairway grass could be as long as92inches.167114113816161616−=−=The putting greens could be as short as13 inch.16Cumulative Review83.36949441411×==×84.3265313326 555×+==Classroom Quiz 0.21.1234169295or 16382424242424++=++=2.1755341241891895382181813518971817 2+=+=+===3.223711111555611733535315151515−=−=−==0.3 Exercises2.Invert the second fraction. Multiply the result bythe first fraction.4.52857 441or 171575 333⋅×=×=⋅6.17131713126342 1317 24×=×=⋅⋅8.351511777×=10.⋅×=×=⋅⋅1583 5852493 83 3912.692 39121183 72 97⋅×=×=⋅⋅14.223 510315or 1213 7177⋅×=×=⋅16.8832423or 2111111111×=×=18.÷=×=13131377979139

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ISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review520.÷=×=771748843222.218999188191211÷=×=×=24.85862 4641261252 655⋅÷=×=×=⋅26.94979792872844 7416÷=×=×=⋅28.56101351051351313116136106251212×=÷=×===××30.341112311312334941241141111××=÷=×==×32.139279841431282822733÷=÷=×==34.÷=÷=××=×==13111553242411421511222152215711536.171151812 421484841541515⋅÷=÷=×=×=38.121811891829 22184421219194⋅=÷=÷=×=×=40.561251555252126262653 2532=÷=÷=×=×=⋅42.⋅⋅×=×=⋅1296 23 331826 3244.51151853 6154or 16186116111111⋅÷=×=×=46.÷=÷=×=×==2192710293939239792137922184 2148.21551535 3315193131515⋅÷=÷=×=×=50.1132 661278221⋅×=×=52.1237237 2142 3353353 515⋅××=××==⋅54.a.12414 6461561515⋅×=×=b.12411513 556156242 32448⋅÷=×=×=⋅56.a.3213253252572572173 749÷=×=×=⋅b.32133 7972572525⋅×=×=58.1511713291484811784139 132 441318÷=÷=×⋅⋅=×=The material can make 18 pullovers.60.115513 5511515351515⋅×10=×=×=The area of her garden is 153 square feet.Cumulative Review61.1111555157515575?×=⇒=×

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra662.777499639763?×=⇒=×Classroom Quiz 0.31.426413 281329132929⋅×=×=2.1511171877521526261212×=×==3.3110291014107 2201271471472972929⋅÷=÷=×=×=0.4 Exercises2.We write 0.42 in words as forty-two hundredths.4.When dividing 96.3 by 10,000 we move thedecimal point 4 places to the left.6.0.721825 18.000.722517 550500==8.0.6915 9.00.6159 00==10.0.16616 1.0000.1666403640364==12.510.5102==14.3570.3510020==16.7753125310 7751000402540.×===×18.==820.081002520.482422444.8or 4105255×===×22.×===×62525252516.25or 610004254424.4 640 234 87...+26.+6.314.208.5019.0128.+33.0100.380175.401208.79130.121 5279 8541 67...−32.5 00323 00361 9996...−34.212 543 60208 94...−36.6 123 42 44818 3620 808...×38.6 321 316321 8966 328 2792...×

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ISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review740.×3.840.001726883840.00652842.×23, 0000.00424 600092 00096.6000or 96.644.0.324839 12.667211 79678187156312312046.3.182.056.51906 15369205164016400∧∧48.6.20.0050.03103010100∧∧50.0.0950.090.008558145450∧∧52.1.36×1000 = 136054.175,318÷1000 = 175.31856.0.00243×100,000 = 24358.3.52÷1000 = 0.0035260.85.54×10,000 = 855,40062.96.12÷10,000 = 0.00961264.×8.2520.0050.041260or 0.0412666.+1.1090.08816.417.59768.25712.or 25,7120.00377.136617152 12 133660∧∧70.25.62×10,000 = 256,20072.14.300.6813.62−74.0.58÷1000 = 0.0005876.13.24452 8528580.8×Chris can drive 580.8 miles.78.1.3×5 = 6.5 milligramsNo; there was 0.3 milligram of copper in the5 liters (or 0.06 milligram per liter) in excess ofthe standard.

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra8Cumulative Review79.⋅÷=÷=⋅==⋅11721741 223524242211 3380.⋅⋅=⋅=⋅⋅⋅3 1233 418272 43 3 3681.12948454845932520100100100100++=+==82.31811651651111152521010101010−−=−=−===Classroom Quiz 0.41.9.00384.63294.3709−2.47.90.073.353×3.25.90.235.9574 61 351 152072070∧∧Use Math to Save Money1.$100, $300, $2000, $8000, $8000, $8000,$12,0002.3×$25 + $50 + $200 + 2×$20= $75 + $50 + $200 + $40= $3653.The three smallest debts are $100 loan, $300loan, and $2000 car loan.4.$20 each, or $405.$2000−$400 = $1600$16007$240≈(rounded to the nearest wholenumber)It will take them 7 more months to pay off thethird smallest debt.6.Answers will vary.How Am I Doing? Sections 0.1−0.4(Available online through MyMathLab or from theInstructor’s Resource Center.)1.⋅==⋅153 535511 5112.⋅==⋅462 2321155 2353.31534 15344123==4.⋅++===54 75285334 77775.×=⇒=×4?462453056306.×=⇒=×5?594598199817.8 = 2⋅2⋅26 = 2⋅315 = 3⋅5LCD = 2⋅2⋅2⋅3⋅5 = 1208.323257777++==9.525 32 215419142114 321 2424242⋅⋅+=+=+=⋅⋅10.+=+⋅⋅=+⋅⋅=+==32111725434311 317 44 33 43368121210112581211.⋅−=−=−=⋅175175 217107189189 2181818

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ISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review912.⋅⋅−=−=−=⋅⋅626 32 718144737 33 721212113.−=−⋅⋅=−⋅⋅=−==13161131585816 811 55 88 51285540407340331 4014.⋅⋅×=×==⋅25145 52 7101174575 99915.⋅×=×=×=11276 27123422121216.84747714371812 422÷=⋅=×==⋅17.÷=÷=×=1171374282334343133918.==0.37538 3.0000.37582 460564040019.==0.83356 5.0000.8364 820182018220.0.0153200 3.0000.0152002 001 0001 0000==21.+15.2303.6000.82119.65122.×3.280.639841 9682.066423.0.453.0156.73.0150.456.72 683353350=∧∧=24.−12.1309.8842.2460.5 Exercises2.The number directly following the word “of”should be the denominator. In this case youshould use3080since 80 follows the word “of.”4.0.54 = 54%6.0.063 = 6.3%8.0.046 = 4.6%10.7.49 = 749%12.5.7 = 570%14.8.674 = 867.4%16.6% = 0.0618.0.62% = 0.0062

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra1020.175% = 1.7522.8.7% = 0.08724.0.1% = 0.00126.200% = 2.00 or 228.7% of 690.07×69 = 4.8330.25% of 6000.25×600 = 15032.154% of 2701.54×270 = 415.834.49 is what percent of 28?==491.75175%2836.What percent of 35 is 28?===2840.880%35538.48 is what percent of 600?4820.088%60025===40.75 is what percent of 30?7552 5250302.%===42.What percent of 440 is 11?110 0252 5440.. %==2.5% of the units were defective.44.28% of 3500.28×350 = 9898 of the new businesses failed.46.1370.761176.11%180≈=About 76.11% had a grandparent not born in theUnited States.48.17%×3690 = 0.17×3690 = 627.30Her monthly cost is $627.30.50.a.65%×18,600 = 12,090He traveled 12,090 miles.b.0.31×12,090 = 3747.90He was paid $3747.90.52.729×688≈700×700 = 490,00054.8192×5984≈8000×6000 = 48,000,00056.+++≈+++=318494613243300500600200160058.300, 00016 5,846, 21320 6, 000, 000≈60.53, 61050, 00050062.57868008≈==62.4.9% of $9321.88≈0.05×$9000 = $45064.85×19×5≈90×20×5 = 9000An estimated $9000 is withdrawn each hour.66.11, 90010, 00025430400≈=It will take an estimated 25 trips.Cumulative Review67.Distance: 69,229.5−68,459.5 = 7707702235=His car achieved 22 miles per gallon.68.Total = 4.6 + 4.5 + 2.9 = 1212Average4.0 inches per month.3==Classroom Quiz 0.51.6.4% of 380 = 0.064×380 = 24.322.247 is what percent of 380?==2470.6565%3803.×≈×≈4498.566721.184000700028, 000, 0000.6 Exercises2.1145251125Area221222224=×=×=1125Cost8.0022504=×=The total cost is $2250.

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ISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review114.a.11254151220522221512541281 251281.××=××==≈It will take 1281 cubic feet to fill the pool.b.7.5 gal1281 cu ft9607.5 galcu ft10, 000 gal×=≈The pool holds 10,000 gallons.c.10 00025000,;=2×4 = 8They should add 8 ounces of chlorinatoreach day.6.Increase from day 1 to day 3+=1151 333Jog:×=×=5153112miles32322Walk:×=×==5357351112miles34341212Rest:×=×==515525124minutes323266Walk:55211miles333×==8.Increase from day 1 to day 5⎛⎞×××==⎜⎟⎝⎠41111425611113333381Jog:×=×==256125631282014mi8128122727She would jog204 27 mileson day 5.10.Answers will vary. Possible answer: Melinda’strainer has the best plan because after 14 daysshe will be jogging and walking a gradualincrease in distances. Over 14 days, Betty’sschedule increases more. The amount of increaseeach day is larger. Eventually it is unrealistic.12.a.100%−12% = 88%0.88×24 = 21.12You get 21.12 oz from a dozen large eggs.0.88×21 = 18.48You get 18.48 oz from a dozen mediumeggs.b.large:1 790 08521 12.$ ./oz;.≈medium:1 390 07518 48.$ ./oz.≈The medium eggs are the better buy.14.a.From 13(b), the budget for food is$14,104.15.$14,104.15×0.20 = $2820.83$14,104.15−$2820.83 = $11,283.32The new food budget is $11,283.32.b.$14,104.15−$11,283.32 = $2820.83$2820.83 would be available to reduce thedebt.16.+=≈=12.5636.2848.840.044%11501150About 4% is deducted for retirement andmedical.18.12.5636.2810.8059.640.055%11501150++=≈=Classroom Quiz 0.61.=650260 tiles2.5It will require 260 tiles to pave the courtyard.2.3% of 495,000 = 0.03×495,000 = 14,850.=≈=+14,85014,8500.4242%20,15014,85035, 000His commission was 42% of his total income.3.2(230) + 2(420) = 460 + 840 = 13002.5×1300 = $3250The fence will cost $3250.Career Exploration Problems1.90% of the first $826 = 0.9($826) = $743.4032% of earnings between $826 and $4980= 0.32($4200−$826)= 0.32($3374)= $1079.68She has no earnings over $4980.Monthly benefit743 401079 681823 08$.$.$.=+=Cora’s monthly benefit will be $1823.08.

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Chapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra122.monthly benefit1823 080 434monthly earnings4200$..$=≈Cora’s benefit is about 43.4% of her pre-retirement earnings.3.a.The reduction at age 66 is 6.7%.100%−6.7% = 93.3% or 0.9330.933($1823.08)≈$1700.93Cora’s monthly benefit will be $1700.93.$1823.08−$1700.93 = $122.15The total by which it would be reduced is$122.15.b.The reduction at age 65 is 13.3%.100%−13.3% = 86.7% or 0.8670.867($1823.08)≈$1580.61Cora’s monthly benefit will be $1580.61.$1823.08−$1580.61 = $242.47The total by which it would be reduced is$242.47.You Try It1.a.1892227933×==×b.451533601544×==×c.341722851755×==×2.a.4215 215201=14 5=b.5377 377352=25 7=3.a.2252102122 5555×++===b.1691541556 9999×++===4.335158408540?×=⇒=×5.a.10 = 2×512 = 2×2×3LCD = 2×2×3×5 = 60b.25 = 5×520 = 2×2×5LCD = 2×2×5×5 = 1006.a.1119129211292992181818××+=+=+=××b.1931933199105248248324242412×−=−=−==×7.a.21828242852723539399999+=+=+==b.512342381551312636366622−=−=−===8.a.52521011311333××==×b.71573 5110212 53 72⋅×=×=⋅⋅c.3631836or 351555×=×=9.a.32351514514228÷=×=b.7775512512712÷=×=10.a.511199933112or 464642488×=×==b.13777472 22312242427271⋅÷=÷=×=×==11.0 87578 7 00086 4605640400..=0 875.=

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