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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Document preview page 1

Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 1

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Solution Manual for Beginning and Intermediate Algebra, 5th Edition

Looking for textbook solutions? Solution Manual for Beginning and Intermediate Algebra, 5th Edition has got you covered with detailed answers to all your textbook questions.

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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 1 preview imageSOLUTIONSMANUALBEGINNING ANDINTERMEDIATEALGEBRAFIFTHEDITIONJohn TobeyNorth Shore Community CollegeDanvers, MassachusettsJeffrey SlaterNorth Shore Community CollegeDanvers, MassachusettsJamie BlairOrange Coast CollegeCosta Mesa, CaliforniaJennifer CrawfordNormandale Community CollegeBloomington, Minnesota
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 2 preview image
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 3 preview imageContentsChapter 01Chapter 118Chapter 237Chapter 374Chapter 4109Chapter 5140Chapter 6162Chapter 7185Chapter 8214Chapter 9240Chapter 10289Chapter 11317Chapter 12339Practice Final Examination364
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 4 preview image
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 5 preview image1Chapter 00.1 Exercises2.13 :1717 is the denominator4.1:317or3176.33 48.205452446×==6×10.818148686×==×12.72184418181×==×14.323211643222×==×16.331133551155×==×18.6397781999×==×20.==31945 1935515422.75457 54777495==24.==64156 4166636526.82513 25833241==28.117927 79117770972==30.15124418 1241515882844404===32.×++===2(45)2202224 555534.×++===1(512)16016151212121236.5(16)565111 6666×++===38.2(63)2182206 3333×++===40.1(109)19019110 9999×++===42.787866=÷136 7861818078136=
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 6 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra244.×=⇒=×5?5630954965446.×=⇒=×5?5525945954548.×=⇒=×13?1333917511735150.10?10440156015460×=⇒=×52.7?75358408540×=⇒=×54.45?4529050100502100×=⇒=×56.205454241064106×==×58.1400702070242012120121×==×60.=++33 is raisins131562.+=++1341315does not contain nuts64.663236814727×===+×37of the students enrolled in 1994 were male.Classroom Quiz 0.11.567878811811×==×2.11(514)11701181514141414×++⇒==3.109191212=912 10910810.2 Exercises2.You must change the fractions to equivalentfractions with a common denominator.4.2117and302030 = 2⋅3⋅520 = 2⋅2⋅5LCD = 2⋅2⋅3⋅5 = 606.51and182418 = 2⋅3⋅324 = 2⋅2⋅2⋅3LCD = 2⋅2⋅2⋅3⋅3 = 728.57and164816 = 2⋅2⋅2⋅248 = 2⋅2⋅2⋅2⋅3LCD = 2⋅2⋅2⋅2⋅3 = 4810.117and122012 = 2⋅2⋅320 = 2⋅2⋅5LCD = 2⋅2⋅3⋅5 = 6012.78and304530 = 2⋅3⋅545 = 3⋅3⋅5LCD = 2⋅3⋅3⋅5 = 9014.139,, and714357 = 714 = 2⋅735 = 5⋅7LCD = 2⋅5⋅7 = 7016.3511,, and812428 = 2⋅2⋅212 = 2⋅2⋅342 = 2⋅3⋅7LCD = 2⋅2⋅2⋅3⋅7 = 168
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 7 preview imageISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review318.5311,and814168 = 2⋅2⋅214 = 2⋅716 = 2⋅2⋅2⋅2LCD = 2⋅2⋅2⋅2⋅7 = 11220.3535811111111++==22.11211293151515155−−===24.31333134952611or 1201520315460606060××+=+=+=××26.434735281513575775353535××−=−=−=××28.3133189817838338242424××+=+=+=××30.27227342125515101521033030306××+=+=+==××32.212321223422319122412224242424×−=−=−=×34.131131313310215515531515153×−=−=−==×36.75795463208311or 249499436363636××+=+=+=××38.47136492110643or 17936363636363++=++=40.134173644121421127146214718168484844184×××++=++×××=++=42.1211132511531553351531011151515215××+−=+−××=+−=44.+−=+−==53159861248324242424446.+=+=+==1125137552127732586862424242448.+=+=+==232038098956734341212121250.−=−=−==23371514875731373354542020202052.831131311339741472415515515151515−=−=−==54.+=+=+==11221366911571034773732121212156.1237172021256333333−=−==58.12112911824799191313131313+=+==60.+=+==193199281430103030301562.2217378511119615713353515151515+=+=+==64.−=−==15315961248242424466.1119177651251642343412121212−=−=−==68.313632614526810810181510444040771401119 40−=−=−==70.255530535171131831818181818+=+=+==
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 8 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra472.32313215512828337614454520202020+=+=+==74.52829224291953283248188888−=−=−==76.112212156105182432431266322412121241312534 12++=++=++==They ran a total of53412 miles.78.31271581712443443213153212121219612416 12116 3+−=+−=+−===There are now116 3 gallons.80.5937737473144inch816816161616−=−=−=It is smaller so it will slide in and out easily.82.11514014192221621616161616+=+=+==The fairway grass could be as long as92inches.167114113816161616−=−=The putting greens could be as short as13 inch.16Cumulative Review83.36949441411×==×84.3265313326 555×+==Classroom Quiz 0.21.1234169295or 16382424242424++=++=2.1755341241891895382181813518971817 2+=+=+===3.223711111555611733535315151515−=−=−==0.3 Exercises2.Invert the second fraction. Multiply the result bythe first fraction.4.52857 441or 171575 333⋅×=×=⋅6.17131713126342 1317 24×=×=⋅⋅8.351511777×=10.⋅×=×=⋅⋅1583 5852493 83 3912.692 39121183 72 97⋅×=×=⋅⋅14.223 510315or 1213 7177⋅×=×=⋅16.8832423or 2111111111×=×=18.÷=×=13131377979139
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 9 preview imageISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review520.÷=×=771748843222.218999188191211÷=×=×=24.85862 4641261252 655⋅÷=×=×=⋅26.94979792872844 7416÷=×=×=⋅28.56101351051351313116136106251212×=÷=×===××30.341112311312334941241141111××=÷=×==×32.139279841431282822733÷=÷=×==34.÷=÷=××=×==13111553242411421511222152215711536.171151812 421484841541515⋅÷=÷=×=×=38.121811891829 22184421219194⋅=÷=÷=×=×=40.561251555252126262653 2532=÷=÷=×=×=⋅42.⋅⋅×=×=⋅1296 23 331826 3244.51151853 6154or 16186116111111⋅÷=×=×=46.÷=÷=×=×==2192710293939239792137922184 2148.21551535 3315193131515⋅÷=÷=×=×=50.1132 661278221⋅×=×=52.1237237 2142 3353353 515⋅××=××==⋅54.a.12414 6461561515⋅×=×=b.12411513 556156242 32448⋅÷=×=×=⋅56.a.3213253252572572173 749÷=×=×=⋅b.32133 7972572525⋅×=×=58.1511713291484811784139 132 441318÷=÷=×⋅⋅=×=The material can make 18 pullovers.60.115513 5511515351515⋅×10=×=×=The area of her garden is 153 square feet.Cumulative Review61.1111555157515575?×=⇒=×
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 10 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra662.777499639763?×=⇒=×Classroom Quiz 0.31.426413 281329132929⋅×=×=2.1511171877521526261212×=×==3.3110291014107 2201271471472972929⋅÷=÷=×=×=0.4 Exercises2.We write 0.42 in words as forty-two hundredths.4.When dividing 96.3 by 10,000 we move thedecimal point 4 places to the left.6.0.721825 18.000.722517 550500==8.0.6915 9.00.6159 00==10.0.16616 1.0000.1666403640364==12.510.5102==14.3570.3510020==16.7753125310 7751000402540.×===×18.==820.081002520.482422444.8or 4105255×===×22.×===×62525252516.25or 610004254424.4 640 234 87...+26.+6.314.208.5019.0128.+33.0100.380175.401208.79130.121 5279 8541 67...−32.5 00323 00361 9996...−34.212 543 60208 94...−36.6 123 42 44818 3620 808...×38.6 321 316321 8966 328 2792...×
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 11 preview imageISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review740.×3.840.001726883840.00652842.×23, 0000.00424 600092 00096.6000or 96.644.0.324839 12.667211 79678187156312312046.3.182.056.51906 15369205164016400∧∧48.6.20.0050.03103010100∧∧50.0.0950.090.008558145450∧∧52.1.36×1000 = 136054.175,318÷1000 = 175.31856.0.00243×100,000 = 24358.3.52÷1000 = 0.0035260.85.54×10,000 = 855,40062.96.12÷10,000 = 0.00961264.×8.2520.0050.041260or 0.0412666.+1.1090.08816.417.59768.25712.or 25,7120.00377.136617152 12 133660∧∧70.25.62×10,000 = 256,20072.14.300.6813.62−74.0.58÷1000 = 0.0005876.13.24452 8528580.8×Chris can drive 580.8 miles.78.1.3×5 = 6.5 milligramsNo; there was 0.3 milligram of copper in the5 liters (or 0.06 milligram per liter) in excess ofthe standard.
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 12 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra8Cumulative Review79.⋅÷=÷=⋅==⋅11721741 223524242211 3380.⋅⋅=⋅=⋅⋅⋅3 1233 418272 43 3 3681.12948454845932520100100100100++=+==82.31811651651111152521010101010−−=−=−===Classroom Quiz 0.41.9.00384.63294.3709−2.47.90.073.353×3.25.90.235.9574 61 351 152072070∧∧Use Math to Save Money1.$100, $300, $2000, $8000, $8000, $8000,$12,0002.3×$25 + $50 + $200 + 2×$20= $75 + $50 + $200 + $40= $3653.The three smallest debts are $100 loan, $300loan, and $2000 car loan.4.$20 each, or $405.$2000−$400 = $1600$16007$240≈(rounded to the nearest wholenumber)It will take them 7 more months to pay off thethird smallest debt.6.Answers will vary.How Am I Doing? Sections 0.1−0.4(Available online through MyMathLab or from theInstructor’s Resource Center.)1.⋅==⋅153 535511 5112.⋅==⋅462 2321155 2353.31534 15344123==4.⋅++===54 75285334 77775.×=⇒=×4?462453056306.×=⇒=×5?594598199817.8 = 2⋅2⋅26 = 2⋅315 = 3⋅5LCD = 2⋅2⋅2⋅3⋅5 = 1208.323257777++==9.525 32 215419142114 321 2424242⋅⋅+=+=+=⋅⋅10.+=+⋅⋅=+⋅⋅=+==32111725434311 317 44 33 43368121210112581211.⋅−=−=−=⋅175175 217107189189 2181818
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 13 preview imageISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review912.⋅⋅−=−=−=⋅⋅626 32 718144737 33 721212113.−=−⋅⋅=−⋅⋅=−==13161131585816 811 55 88 51285540407340331 4014.⋅⋅×=×==⋅25145 52 7101174575 99915.⋅×=×=×=11276 27123422121216.84747714371812 422÷=⋅=×==⋅17.÷=÷=×=1171374282334343133918.==0.37538 3.0000.37582 460564040019.==0.83356 5.0000.8364 820182018220.0.0153200 3.0000.0152002 001 0001 0000==21.+15.2303.6000.82119.65122.×3.280.639841 9682.066423.0.453.0156.73.0150.456.72 683353350=∧∧=24.−12.1309.8842.2460.5 Exercises2.The number directly following the word “of”should be the denominator. In this case youshould use3080since 80 follows the word “of.”4.0.54 = 54%6.0.063 = 6.3%8.0.046 = 4.6%10.7.49 = 749%12.5.7 = 570%14.8.674 = 867.4%16.6% = 0.0618.0.62% = 0.0062
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 14 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra1020.175% = 1.7522.8.7% = 0.08724.0.1% = 0.00126.200% = 2.00 or 228.7% of 690.07×69 = 4.8330.25% of 6000.25×600 = 15032.154% of 2701.54×270 = 415.834.49 is what percent of 28?==491.75175%2836.What percent of 35 is 28?===2840.880%35538.48 is what percent of 600?4820.088%60025===40.75 is what percent of 30?7552 5250302.%===42.What percent of 440 is 11?110 0252 5440.. %==2.5% of the units were defective.44.28% of 3500.28×350 = 9898 of the new businesses failed.46.1370.761176.11%180≈=About 76.11% had a grandparent not born in theUnited States.48.17%×3690 = 0.17×3690 = 627.30Her monthly cost is $627.30.50.a.65%×18,600 = 12,090He traveled 12,090 miles.b.0.31×12,090 = 3747.90He was paid $3747.90.52.729×688≈700×700 = 490,00054.8192×5984≈8000×6000 = 48,000,00056.+++≈+++=318494613243300500600200160058.300, 00016 5,846, 21320 6, 000, 000≈60.53, 61050, 00050062.57868008≈==62.4.9% of $9321.88≈0.05×$9000 = $45064.85×19×5≈90×20×5 = 9000An estimated $9000 is withdrawn each hour.66.11, 90010, 00025430400≈=It will take an estimated 25 trips.Cumulative Review67.Distance: 69,229.5−68,459.5 = 7707702235=His car achieved 22 miles per gallon.68.Total = 4.6 + 4.5 + 2.9 = 1212Average4.0 inches per month.3==Classroom Quiz 0.51.6.4% of 380 = 0.064×380 = 24.322.247 is what percent of 380?==2470.6565%3803.×≈×≈4498.566721.184000700028, 000, 0000.6 Exercises2.1145251125Area221222224=×=×=1125Cost8.0022504=×=The total cost is $2250.
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 15 preview imageISM: Beginning and Intermediate AlgebraChapter 0:Prealgebra Review114.a.11254151220522221512541281 251281.××=××==≈It will take 1281 cubic feet to fill the pool.b.7.5 gal1281 cu ft9607.5 galcu ft10, 000 gal×=≈The pool holds 10,000 gallons.c.10 00025000,;=2×4 = 8They should add 8 ounces of chlorinatoreach day.6.Increase from day 1 to day 3+=1151 333Jog:×=×=5153112miles32322Walk:×=×==5357351112miles34341212Rest:×=×==515525124minutes323266Walk:55211miles333×==8.Increase from day 1 to day 5⎛⎞×××==⎜⎟⎝⎠41111425611113333381Jog:×=×==256125631282014mi8128122727She would jog204 27 mileson day 5.10.Answers will vary. Possible answer: Melinda’strainer has the best plan because after 14 daysshe will be jogging and walking a gradualincrease in distances. Over 14 days, Betty’sschedule increases more. The amount of increaseeach day is larger. Eventually it is unrealistic.12.a.100%−12% = 88%0.88×24 = 21.12You get 21.12 oz from a dozen large eggs.0.88×21 = 18.48You get 18.48 oz from a dozen mediumeggs.b.large:1 790 08521 12.$ ./oz;.≈medium:1 390 07518 48.$ ./oz.≈The medium eggs are the better buy.14.a.From 13(b), the budget for food is$14,104.15.$14,104.15×0.20 = $2820.83$14,104.15−$2820.83 = $11,283.32The new food budget is $11,283.32.b.$14,104.15−$11,283.32 = $2820.83$2820.83 would be available to reduce thedebt.16.+=≈=12.5636.2848.840.044%11501150About 4% is deducted for retirement andmedical.18.12.5636.2810.8059.640.055%11501150++=≈=Classroom Quiz 0.61.=650260 tiles2.5It will require 260 tiles to pave the courtyard.2.3% of 495,000 = 0.03×495,000 = 14,850.=≈=+14,85014,8500.4242%20,15014,85035, 000His commission was 42% of his total income.3.2(230) + 2(420) = 460 + 840 = 13002.5×1300 = $3250The fence will cost $3250.Career Exploration Problems1.90% of the first $826 = 0.9($826) = $743.4032% of earnings between $826 and $4980= 0.32($4200−$826)= 0.32($3374)= $1079.68She has no earnings over $4980.Monthly benefit743 401079 681823 08$.$.$.=+=Cora’s monthly benefit will be $1823.08.
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Solution Manual for Beginning and Intermediate Algebra, 5th Edition - Page 16 preview imageChapter 0:Prealgebra ReviewISM: Beginning and Intermediate Algebra122.monthly benefit1823 080 434monthly earnings4200$..$=≈Cora’s benefit is about 43.4% of her pre-retirement earnings.3.a.The reduction at age 66 is 6.7%.100%−6.7% = 93.3% or 0.9330.933($1823.08)≈$1700.93Cora’s monthly benefit will be $1700.93.$1823.08−$1700.93 = $122.15The total by which it would be reduced is$122.15.b.The reduction at age 65 is 13.3%.100%−13.3% = 86.7% or 0.8670.867($1823.08)≈$1580.61Cora’s monthly benefit will be $1580.61.$1823.08−$1580.61 = $242.47The total by which it would be reduced is$242.47.You Try It1.a.1892227933×==×b.451533601544×==×c.341722851755×==×2.a.4215 215201=14 5=b.5377 377352=25 7=3.a.2252102122 5555×++===b.1691541556 9999×++===4.335158408540?×=⇒=×5.a.10 = 2×512 = 2×2×3LCD = 2×2×3×5 = 60b.25 = 5×520 = 2×2×5LCD = 2×2×5×5 = 1006.a.1119129211292992181818××+=+=+=××b.1931933199105248248324242412×−=−=−==×7.a.21828242852723539399999+=+=+==b.512342381551312636366622−=−=−===8.a.52521011311333××==×b.71573 5110212 53 72⋅×=×=⋅⋅c.3631836or 351555×=×=9.a.32351514514228÷=×=b.7775512512712÷=×=10.a.511199933112or 464642488×=×==b.13777472 22312242427271⋅÷=÷=×=×==11.0 87578 7 00086 4605640400..=0 875.=
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Beginning Algebra by John Tobey, Je...

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