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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Document preview page 1

Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 1

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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition

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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 1 preview imageTESTITEMFILE(DOWNLOADONLY)PRECALCULUSEnhanced with Graphing UtilitiesSEVENTH EDITIONSullivan and Sullivan
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 2 preview image
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 3 preview imageCh. 1Graphs1.1The Distance and Midpoint Formulas; Graphing Utilities; Introduction to Graphing Equations1Use the Distance FormulaMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Find the distance d(P1, P2) between the points P1 and P2.1)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)34B)2C) 3D) 12)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A)113B)15C) 56D) 1Page 1
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 4 preview image3)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A) 35B) 273C) 27D) 94)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A) 229B) 8421C) 84D) 65) P1=(-4,-4); P2=(-4, 4)A) 8B) 22C) 9D) 76) P1=(1,-5); P2=(-2,-1)A) 5B) 25C) 6D) 107) P1=(0,-3); P2=(4,-3)A) 4B) 3C) 5D) 168) P1=(0, 0); P2=(10, 2)A) 226B) 104C) 12D) 259) P1=(7, 1); P2=(-1,-2)A)73B)55C) 24D) 510) P1=(7,-6); P2=(3,-4)A) 25B) 123C) 12D) 6Page 2
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 5 preview image11) P1=(-1,-5); P2=(2, 7)A) 317B) 13515C) 135D) 912) P1=(0.9, 0.4); P2=(1.4,-2.3) Round to three decimal places, if necessary.A) 2.746B) 16C) 8.683D) 2.846Decide whether or not the points are the vertices of a right triangle.13) (5, 3), (14, 3), (14, 8)A) YesB) No14) (-3,-3), (-1, 1), (1, 0)A) YesB) No15) (-2,-5), (4,-3), (3,-8)A) YesB) No16) (8, 7), (14, 9), (20, 2)A) YesB) NoSolve the problem.17) Find all values of k so that the given points are29 units apart.(-5, 5), (k, 0)A)-3,-7B)-7C) 3, 7D) 718) Find the area of the right triangle ABC with A=(-2, 7), B=(7,-1), C=(3, 9).A) 29 square unitsB) 58 square unitsC)582square unitsD)292square units19) Find all the points having an x-coordinate of 9 whose distance from the point (3,-2) is 10.A) (9, 6), (9,-10)B) (9, 2), (9,-4)C) (9,-12), (9, 8)D) (9, 13), (9,-7)20) A middle school's baseball playing field is a square, 50 feet on a side. How far is it directly from homeplate to second base (the diagonal of the square)? If necessary, round to the nearest foot.A) 71 feetB) 72 feetC) 70 feetD) 78 feet21) A motorcycle and a car leave an intersection at the same time. The motorcycle heads north at an averagespeed of 20 miles per hour, while the car heads east at an average speed of 48 miles per hour. Find anexpression for their distance apart in miles at the end of t hours.A) 52t milesB) t68 milesC) 52t milesD) 2t13 miles22) A rectangular city park has a jogging loop that goes along a length, width, and diagonal of the park. To thenearest yard, find the length of the jogging loop, if the length of the park is 125 yards and its width is 75yards.A) 346 yardsB) 146 yardsC) 345 yardsD) 145 yardsPage 3
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 6 preview image23) Find the length of each side of the triangle determined by the three points P1, P2, and P3. State whetherthe triangle is an isosceles triangle, a right triangle, neither of these, or both.P1=(-5,-4), P2=(-3, 4), P3=(0,-1)A) d(P1, P2)=217; d(P2, P3)=34; d(P1, P3)=34bothB) d(P1, P2)=217; d(P2, P3)=34; d(P1, P3)=34isosceles triangleC) d(P1, P2)=217; d(P2, P3)=34; d(P1, P3)=52right triangleD) d(P1, P2)=217; d(P2, P3)=34; d(P1, P3)=52neither2Use the Midpoint FormulaMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Find the midpoint of the line segment joining the points P1 and P2.1) P1=(8, 1); P2=(7, 8)A) ( 152 , 92 )B) (15, 9)C) (1,-7)D) ( 92 , 152 )2) P1=(3, 1); P2=(4,-1)A)72 , 0B)-12 , 1C)-1, 2D) 7, 03) P1=(7, 1); P2=(-16,-16)A)-92 ,-152B)232 , 172C)-9,-15D) 9, 154) P1=(-0.1,-0.8); P2=(2,-1.5)A) (0.95,-1.15)B) (-1.15, 0.95)C) (1.05,-0.35)D) (-0.35, 1.05)5) P1=(x, 6); P2=(0, 7)A)x2 , 132B) x, 13C)-x2 , 1D) x, 1326) P1=(9x, 3); P2=(10x, 8)A)19x2, 112B) 19x, 11C) x, 5D)11x2, 192Solve the problem.7) If (3, 3) is the endpoint of a line segment, and (8, 7) is its midpoint, find the other endpoint.A) (13, 11)B) (13,-1)C) (-7,-5)D) (11, 13)8) If (3, 2) is the endpoint of a line segment, and (2, 0) is its midpoint, find the other endpoint.A) (1,-2)B) (1, 4)C) (5, 6)D) (-1, 0)9) If (1,-2) is the endpoint of a line segment, and (3,-7) is its midpoint, find the other endpoint.A) (5,-12)B) (5, 3)C) (-3, 8)D) (-9, 2)Page 4
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 7 preview image10) If (-10, 2) is the endpoint of a line segment, and (-11, 6) is its midpoint, find the other endpoint.A) (-12, 10)B) (-12,-2)C) (-8,-6)D) (-2, 0)11) The medians of a triangle intersect at a point. The distance from the vertex to the point is exactlytwo-thirds of the distance from the vertex to the midpoint of the opposite side. Find the exact distance ofthat point from the vertex A(3, 4) of a triangle, given that the other two vertices are at (0, 0) and (8, 0).A) 2173B)173C) 2D) 83Page 5
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 8 preview image3Graph Equations by Plotting PointsMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Plot the point in the xy-plane. Tell in which quadrant or on what axis the point lies.1) (2, 4)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5Quadrant IB)x-55y5-5x-55y5-5Quadrant IC)x-55y5-5x-55y5-5Quadrant IID)x-55y5-5x-55y5-5Quadrant IVPage 6
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 9 preview image2) (-1, 3)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5Quadrant IIB)x-55y5-5x-55y5-5Quadrant IVC)x-55y5-5x-55y5-5Quadrant ID)x-55y5-5x-55y5-5Quadrant IIIPage 7
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 10 preview image3) (3,-4)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5Quadrant IVB)x-55y5-5x-55y5-5Quadrant IIC)x-55y5-5x-55y5-5Quadrant IIID)x-55y5-5x-55y5-5Quadrant IPage 8
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 11 preview image4) (-4,-5)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5Quadrant IIIB)x-55y5-5x-55y5-5Quadrant IIIC)x-55y5-5x-55y5-5Quadrant IVD)x-55y5-5x-55y5-5Quadrant IIPage 9
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 12 preview image5) (0,-3)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5y-axisB)x-55y5-5x-55y5-5x-axisC)x-55y5-5x-55y5-5Quadrant IID)x-55y5-5x-55y5-5y-axisPage 10
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 13 preview image6) (5, 0)x-55y5-5x-55y5-5A)x-55y5-5x-55y5-5x-axisB)x-55y5-5x-55y5-5y-axisC)x-55y5-5x-55y5-5Quadrant IID)x-55y5-5x-55y5-5x-axisDetermine whether the given point is on the graph of the equation.7) Equation: y=x4-xPoint: (0, 0)A) YesB) No8) Equation: x2-y2=4Point: (2,2)A) NoB) YesPage 11
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 14 preview imageGraph the equation by plotting points.9) y=x+1x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page 12
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 15 preview image10) y=3x-9x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page 13
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 16 preview image11) y=-x2+9x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page 14
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 17 preview image12) 5x+3y=15x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page 15
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 18 preview image13) x2+y=1x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page 16
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 19 preview image4Graph Equations Using a Graphing UtilityMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Determine the coordinates of the point shown. Tell in which quadrant the point lies. Assume the coordinates areintegers.1)A) (-4, 6); quadrant IIB) (-4, 3); quadrant IIC) (-4, 6); quadrant ID) (-4, 3); quadrant ISelect a setting so that each of the given points will lie in the viewing window.2) (8, 3), (5, 1), (9, 19)A)B)C)D)Page 17
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 20 preview imageDetermine the viewing window used.3)A)B)C)D)Page 18
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 21 preview imageGraph the equation using a graphing utility.4) y=2x+1A)B)C)D)5) 2x-3y=3A)B)C)D)Page 19
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 22 preview image6) y=-2x2+9A)B)C)D)7) 3x2-2y=56A)B)C)D)Page 20
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 23 preview image5Use a Graphing Utility to Create TablesMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Use a graphing utility to create a table that displays the points on the graph of the given equation for x= -3,-2,-1,0, 1, 2, and 3.1) y=3x+5A)B)C)D)2) 6x+2y=28A)B)C)D)Page 21
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 24 preview image3) y=-3x2+10A)B)C)D)4) 4x2-2y=16A)B)C)D)Page 22
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 25 preview image6Find Intercepts from a GraphMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.List the intercepts of the graph.1)x-10-5510y105-5-10x-10-5510y105-5-10A) (-2, 0), (2, 0)B) (0,-2), (2, 0)C) (0,-2), (0, 2)D) (-2, 0), (0, 2)2)x-55y5-5x-55y5-5A) (0, 1)B) (0, 0)C) (1, 1)D) (1, 0)Page 23
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 26 preview image3)x--22y54321-1-2-3-4-5x--22y54321-1-2-3-4-5A)-π2 , 0 , (0, 3),π2 , 0B)-π2 , 0 , (3, 0),π2 , 0C) 0,-π2 , (3, 0), 0,π2D) 0,-π2 , (0, 3), 0,π24)x-10-5510y105-5-10x-10-5510y105-5-10A) (-2, 0), (0, 8), (4, 0)B) (-2, 0), (0, 8), (0, 4)C) (0,-2), (8, 0), (0, 4)D) (0,-2), (0, 8), (4, 0)5)x-10-5510y105-5-10x-10-5510y105-5-10A) (-1, 0)B) (0,-1)C) (1, 0)D) (0, 1)Page 24
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 27 preview image6)x-10-5510y105-5-10x-10-5510y105-5-10A) (-6, 0), (0,-6), (0, 6), (6, 0)B) (-6, 0), (0, 6)C) (-6, 0), (0,-6), (0, 0), (0, 6), (6, 0)D) (0, 6), (6, 0)7)x-10-5510y105-5-10x-10-5510y105-5-10A) (-4, 0), (1, 0) (-5, 0), (0,-4)B) (-4, 0), (0,-4), (0, 1), (0,-5)C) (4, 0), (1, 0), (5, 0), (0,-4)D) (-4, 0), (0, 4), (0, 1), (0, 5)8)A) (-4, 0), (0, 4), (4, 0)B) (-2, 0), (0, 2), (2, 0)C) (-2, 0), (0, 4), (2, 0)D) (-2, 0), (2, 0)Page 25
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 28 preview image7Use a Graphing Utility to Approximate InterceptsMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Graph the equation using a graphing utility. Use a graphing utility to approximate the intercepts rounded to twodecimal places, if necessary. Use the TABLE feature to help establish the viewing window.1) y=-2x+15A) (0, 15), (7.5, 0)B) (0, 15), (-7.5, 0)C) (0,-15), (7.5, 0)D) (0, 15), (-7.5, 0), (7.5, 0)2) y=-4x+15A) (0, 15), (3.75, 0)B) (0, 3.75), (15, 0)C) (0, 15), (-3.75, 0)D) (0,-3.75), (15, 0)3) y=3x2-19A) (0,-19), (-2.52, 0), (2.52, 0)B) (0,-19), (2.52, 0)C) (0, 19), (-2.52, 0), (2.52, 0)D) (0,-19), (-2.51, 0), (2.51, 0)4) y=5x2-13A) (0,-13), (1.61, 0), (-1.61, 0)B) (0, 1.61), (0,-1.61), (-13, 0)C) (0,-13), (2.60, 0), (-2.60, 0)D) (0, 2.60), (0,-2.60), (-13, 0)5) 3x-4y=56A) (0,-14), (18.67, 0)B) (0,-14), (18.66, 0)C) (0,-14), (-18.67, 0), (18.67, 0)D) (0, 14), (18.67, 0)6) 6x-5y=67A) (0,-13.40), (11.17, 0)B) (0, 11.17), (-13.40, 0)C) (0, 13.40), (-11.17,0)D) (0,-13.41), (11.18, 0)7) 3x2-5y=34A) (0,-6.8), (-3.37, 0), (3.37, 0)B) (0,-6.8), (-3.36, 0), (3.36, 0)C) (0, 6.8), (-3.37, 0), (3.37, 0)D) (0,-6.8), (3.37, 0)8) 4x2-5y=68A) (0,-13.60), (4.12, 0), (-4.12, 0)B) (0, 4.12), (0,-4.12), (-13.60, 0)C) (0,-13.59), (4.13, 0), (-4.13, 0)D) (0, 13.60), (4.12, 0), (-4.12, 0)1.2Intercepts; Symmetry; Graphing Key Equations1Find Intercepts from an EquationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.List the intercepts for the graph of the equation.1) y=x-5A) (5, 0), (0,-5)B) (-5, 0), (0, 5)C) (5, 0), (0, 5)D) (-5, 0), (0,-5)2) y=-5xA) (0, 0)B) (0,-5)C) (-5, 0)D) (-5,-5)3) y2=x+16A) (0,-4), (-16, 0), (0, 4)B) (-4, 0), (0,-16), (4, 0)C) (0,-4), (16, 0), (0, 4)D) (4, 0), (0, 16), (0,-16)Page 26
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 29 preview image4) y=8 xA) (0, 0)B) (1, 0)C) (0, 1)D) (1, 1)5) x2+y-25=0A) (-5, 0), (0, 25), (5, 0)B) (-5, 0), (0,-25), (5, 0)C) (0,-5), (25, 0), (0, 5)D) (5, 0), (0, 25), (0,-25)6) 4x2+9y2=36A) (-3, 0), (0,-2), (0, 2), (3, 0)B) (-2, 0), (-3, 0), (3, 0), (2, 0)C) (-9, 0), (0,-4), (0, 4), (9, 0)D) (-4, 0), (-9, 0), (9, 0), (4, 0)7) 9x2+y2=9A) (-1, 0), (0,-3), (0, 3), (1, 0)B) (-1, 0), (0,-9), (0, 9), (1, 0)C) (-3, 0), (0,-1), (0, 1), (3, 0)D) (-9, 0), (0,-1), (0, 1), (9, 0)8) y=x3-125A) (0,-125), (5, 0)B) (-125, 0), (0, 5)C) (0,-5), (0, 5)D) (0,-5), (-5, 0)9) y=x4-1A) (0,-1), (-1, 0), (1, 0)B) (0,-1)C) (0, 1), (-1, 0), (1, 0)D) (0, 1)10) y=x2+11x+28A) (-7, 0), (-4, 0), (0, 28)B) (7, 0), (4, 0), (0, 28)C) (0,-7), (0,-4), (28, 0)D) (0, 7), (0, 4), (28, 0)11) y=x2+16A) (0, 16)B) (0, 16), (-4, 0), (4, 0)C) (16, 0), (0,-4), (0, 4)D) (16, 0)12) y=8xx2+64A) (0, 0)B) (-8, 0), (0, 0), (8, 0)C) (-64, 0), (0, 0), (64, 0)D) (0,-8), (0, 0), (0, 8)13) y=x2-255x4A) (-5, 0), (5, 0)B) (0, 0)C) (-25, 0), (0, 0), (25, 0)D) (0,-5), (0, 5)Page 27
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 30 preview image2Test an Equation for SymmetryMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.Plot the point A. Plot the point B that has the given symmetry with point A.1) A=(-5, 4); B is symmetric to A with respect to the y-axisx-5-4-3-2-112345y54321-1-2-3-4-5x-5-4-3-2-112345y54321-1-2-3-4-5A)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABB)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABC)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABD)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABPage 28
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Test Bank for Precalculus Enhanced with Graphing Utilities , 7th Edition - Page 31 preview image2) A=(0,-2); B is symmetric to A with respect to the originx-5-4-3-2-112345y54321-1-2-3-4-5x-5-4-3-2-112345y54321-1-2-3-4-5A)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABB)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABC)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABD)x-5-4-3-2-112345y54321-1-2-3-4-5ABx-5-4-3-2-112345y54321-1-2-3-4-5ABPage 29
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Precalculus by Michael Sullivan

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