AP Calculus AB: 10.7.2 Why Shells Can Be Better Than Washers
This set explains scenarios where the shell method simplifies volume calculations compared to the washer method, especially when washers require splitting integrals or complicated algebra. It emphasizes how shells avoid multiple integrals by stacking cylindrical layers and demonstrates setting up integrals using radius, height, and thickness in terms of x.
Why Shells Can Be Better Than Washers
Key Terms
Why Shells Can Be Better Than Washers
•Using the shell method, the volume V of a solid of revolution is given by
, where x is the radius and
h(x) is the height of an arbitrary she...
note
Consider the solid of revolution described on the left. Start by graphing it.
Notice that if you use the washer method to ev...
Find the volume of the solid of revolution generated by rotating about y = a the region bounded by the loop of the given relation 2ay 2 = x (a − x)2 for 0 ≤ x ≤ a and a > 0
8√2/15πa^3
Consider a region bounded by curves y = x and y = x 2 rotated about the x‑axis. What is the volume of the resulting solid?
2π/15
What is the volume of the solid of revolution obtained by rotating the region bounded by the curves x = y 3 − y 4 and x = 0 about the line y = −2?
4π/15
True or false?
Consider the area bounded by the functions y = f (x), or x = g ( y), and the lines x = a and x = b, for b > a ≥ 0 and d > c ≥ 0 as shown. The volume of the solid of revolution generated by sweeping the region around the y‑axis can best be calculated using the washer method. The thickness of the washers should be dy, and you should use the product of the cross-sectional area of the washers and the elemental thickness dy.
false
Related Flashcard Decks
| Term | Definition |
|---|---|
Why Shells Can Be Better Than Washers | •Using the shell method, the volume V of a solid of revolution is given by |
note |
|
Find the volume of the solid of revolution generated by rotating about y = a the region bounded by the loop of the given relation 2ay 2 = x (a − x)2 for 0 ≤ x ≤ a and a > 0 | 8√2/15πa^3 |
Consider a region bounded by curves y = x and y = x 2 rotated about the x‑axis. What is the volume of the resulting solid? | 2π/15 |
What is the volume of the solid of revolution obtained by rotating the region bounded by the curves x = y 3 − y 4 and x = 0 about the line y = −2? | 4π/15 |
True or false? | false |