AP Calculus AB: 12.3.1 The First Type of Improper Integral
This content introduces improper integrals, which occur when the interval of integration is infinite or the integrand is undefined within the interval. It explains that some improper integrals can yield a finite area and therefore converge, while others result in an infinite area and diverge. The convergence or divergence depends on the behavior of the function as it approaches the bounds of integration.
The First Type of Improper Integral
Key Terms
The First Type of Improper Integral
An improper integral is a definite integral with one of the following properties: the integration takes place over an infinite interval, or the int...
note
A definite integral is considered an improper integral if it has one of these properties:
· the integration is over an infinite interval...
Evaluate ∫∞ 25 250,000/x^3dx.
200
Which of the following best describes the red region under the curve for y = 1 / x^ 2?
The red region is dropping in height as x increases. As a result, the change in the area decreases as x increases
Which of the following statements correctly describes improper integrals?
An improper integral that has a defined numerical value converges. Otherwise the improper integral diverges.
Evaluate ∫∞ 1 1/√x dx
The improper integral diverges.
Related Flashcard Decks
| Term | Definition |
|---|---|
The First Type of Improper Integral | An improper integral is a definite integral with one of the following properties: the integration takes place over an infinite interval, or the integrand is undefined at a point within the interval of integration. |
note |
|
Evaluate ∫∞ 25 250,000/x^3dx. | 200 |
Which of the following best describes the red region under the curve for y = 1 / x^ 2? | The red region is dropping in height as x increases. As a result, the change in the area decreases as x increases |
Which of the following statements correctly describes improper integrals? | An improper integral that has a defined numerical value converges. Otherwise the improper integral diverges. |
Evaluate ∫∞ 1 1/√x dx | The improper integral diverges. |
Which of the following is not an improper integral? | ∫−2 0 x dx |
Which of the following statements is true for ∫ ∞ 0 e^−x dx? | The integral is improper and converges to 1. |
Evaluate ∫ ∞ 0 cosx dx. | The improper integral diverges. |
Which of the following best explains why these two improper integrals differ from one another? | Improper Integral A is convergent because it approaches a value of 1. |