AP Calculus AB: 6.2.1 Using Implicit Differentiation
This flashcard set focuses on applying implicit differentiation to find derivatives of equations involving multiple variables. It emphasizes using the chain rule and product rule within the process and highlights the importance of evaluating derivatives at specific points on the original relation by substituting both 𝑥 and 𝑦 values.
Using Implicit Differentiation
Key Terms
Using Implicit Differentiation
• Find the derivative of a relation by differentiating each side of its equation implicitly and solving for the derivative as an unknown. This proc...
note
Implicit differentiation often produces a derivative expressed in terms of more than one variable. When evaluating the slope of a line tang...
Given the equation 1−ln (xy) = e^y, find dy dx.
dy/dx=−y/xye^y+x
Given the equation xy=5,find dy/dx.
dy/dx=−y/x
Given the equation sinxy=1/2,find dy/dx.
dy/dx=−y/x
Given the equation x^2y+y^2x=0,find dy/dx.
dy/dx=−2xy−y^2/2xy+x^2
Related Flashcard Decks
| Term | Definition |
|---|---|
Using Implicit Differentiation | • Find the derivative of a relation by differentiating each side of its equation implicitly and solving for the derivative as an unknown. This process is called implicit differentiation. |
note |
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Given the equation 1−ln (xy) = e^y, find dy dx. | dy/dx=−y/xye^y+x |
Given the equation xy=5,find dy/dx. | dy/dx=−y/x |
Given the equation sinxy=1/2,find dy/dx. | dy/dx=−y/x |
Given the equation x^2y+y^2x=0,find dy/dx. | dy/dx=−2xy−y^2/2xy+x^2 |
Given x/y=1/9,find dy/dx. | dy/dx=9 |
Suppose a curve is defined by the equation (6−x)y^2=x^3. What is the equation of the line tangent to the curve at (3, 3)? | y=2x−3 |
Given the equation2x+2y+xy^2=5,find dy/dx. | dy/dx=−2+y^−2/2−2xy^−3 |
Suppose a curve is defined by the equation y^2=x^3(2−x). What is the equation of the line tangent to the curve at (1,−1)? | y=−x |
Given the equation x^2+3x=y^2+y−6,find dy/dx. | dy/dx=2x+3/2y+1 |
Given cos^3(sinxy)=k where k is some constant,find dxdy | dx/dy=−x/y |
Given the equation xy=cotxy,find dy/dx. | dy/dx=−y/x |
Given sin^3(cosxy)=k where k is some constant, find dy/dx. | dy/dx=−y/x |