AP Calculus AB: 7.2.2 Using the Tangent Line Approximation Formula
These flashcards explain the tangent line approximation formula, which uses the derivative at a known point to approximate function values near that point. The cards cover the process of selecting an easy point, calculating the slope via the derivative, and applying the formula for practical approximations of functions like exponentials, roots, and logarithms.
Using the Tangent Line Approximation Formula
Key Terms
Using the Tangent Line Approximation Formula
The tangent line approximation formula is f(x+delta x) = f(x) + f’(x)(delta x)
note
The process of finding a linear approximation can be
described by a general formula.Use the linear approximation formula to approximate e^2.1.
e^2.1≈11e^2/10
Use the linear approximation formula to approximate 3√7.9.
√7.9≈239/120
Use the linear approximation formula to approximate ln 1.1.
ln1.1≈1/10
Find the linearization of the function f(x)=√x+8 at a=1.
y=x/6+17/6
Related Flashcard Decks
| Term | Definition |
|---|---|
Using the Tangent Line Approximation Formula | The tangent line approximation formula is f(x+delta x) = f(x) + f’(x)(delta x) |
note |
|
Use the linear approximation formula to approximate e^2.1. | e^2.1≈11e^2/10 |
Use the linear approximation formula to approximate 3√7.9. | √7.9≈239/120 |
Use the linear approximation formula to approximate ln 1.1. | ln1.1≈1/10 |
Find the linearization of the function f(x)=√x+8 at a=1. | y=x/6+17/6 |
What is the largest interval of x for which the linear approximation √1+x≈1+x/2 is accurate to within .2? | (.4−√1.6,.4+√1.6) |
Use the linear approximation formula to approximate 3√27.1. | √27.1≈811/270 |
Use the linear approximation formula to approximate e^3.1. | e3.1≈11e^3/10 |
Use the linear approximation formula to approximate sec 99π/100 | sec99π/100≈−1 |
Use the linear approximation formula to approximate √16.2. |
|
Use the linear approximation formula to approximate the root. | √3.9≈79/40 |
Use the linear approximation formula to approximate tan 0.1. | tan.1≈0.1 |
Use the linear approximation formula to approximate √15.9. | √15.9≈319/80 |