QQuestionPhysics
QuestionPhysics
Calculate the specific gravity of Mercury given the following:
Density of Mercury = 844.9 lb/ft^3
Density of Water = 62.43 lb/ft^3
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Understand the Definition of Specific Gravity
- $$\rho_{water}$$ is the density of water
Specific gravity is defined as the ratio of the density of a substance to the density of a reference substance (typically water) at a standard temperature and pressure. The formula for specific gravity is: Where:
Step 3:: Identify the Given Values
- Density of Mercury ($$\rho_{Mercury}$$) = $$844.9 \text{ lb/ft}^{3}
- Density of Water (\rho_{water}) = 62.43 \text{ lb/ft}^{3}
Step 4:: Calculate Specific Gravity
SG_{Mercury} = \frac{844.9 \text{ lb/ft}^{3}}{62.43 \text{ lb/ft}^{3}}
Step 5:: Perform the Calculation
SG_{Mercury} = 13.53
Final Answer
The specific gravity of Mercury is 13.53.
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