QQuestionPhysics
QuestionPhysics
Convert the density of iron from 7.874 g/cm³ to kilograms per cubic meter.
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Identify the Given Information
- Original density of iron: $$7.874 \frac{g}{cm^{3}}
- We need to convert this to \frac{kg}{m^{3}}
Step 3:: Understand the Conversion Factors
- 1 g = $$10^{-3}$$ kg
- 1 cm³ = 10^{- 6} m³
Step 4:: Perform the Conversion Calculation
\begin{align*}
Step 5:874 \frac{g}{cm^{3}} &= 7.874 \times \frac{10^{- 3} \mathrm{kg}}{10^{- 6} \mathrm{m}^{3}} \
&= 7.874 \times 10^{3} \frac{\mathrm{kg}}{\mathrm{m}^{3}}
\end{align*}
Step 6:: Simplify the Result
7,874 \frac{\mathrm{kg}}{\mathrm{m}^{3}}
Final Answer
The density of iron is 7,874 \frac{\mathrm{kg}}{\mathrm{m}^{3}}.
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