QQuestionPhysics
QuestionPhysics
The specific weight of water is 9810 N/m^3. A block of composite has a volume of 1.8 m^3 and has a mass of 1,539 kg. What is the specific gravity of the composite? Provide your answer with two decimals.
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Answer
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Step 1:: Determine the volume of the block in meters cubed.
V = 1.8, mathrm{~m}^3
The problem states that the volume of the block is 1.8 m^3, so there's no need for further calculation here. We can represent this as:
Step 2:: Calculate the mass of water with an equivalent volume to the block.
m = 1.8, mathrm{~m}^3 times 9810,frac{mathrm{N}}{mathrm{m}^3} = 17,658, mathrm{~N}cdotmathrm{m}^3
To find the mass of water with an equivalent volume, we can use the following formula: Where: - m is the mass of the water - V is the volume of the water (which is equal to the volume of the block) - g is the specific weight of water Substituting the given values and the volume from Step 1, we get:
Step 3:: Convert the mass of water to kilograms.
m = 17,658, mathrm{~N} = 17,658, mathrm{~kg}
Since 1 N (Newton) is equal to 1 kg.m/s², we can convert the mass from Newtons to kilograms:
Step 4:: Calculate the specific gravity of the composite.
SG = frac{855, mathrm{~kg/m}^3}{9810, mathrm{~kg/m}^3} = 0.087
Specific gravity is defined as the ratio of the density of a substance to the density of a reference substance (in this case, water). Since the mass and volume of the water and composite are known, we can calculate the specific gravity (SG) as follows: Given that the mass of the composite is 1,539 kg and its volume is 1.8 m³, the density of the composite is: Since the mass and volume of the water are 17,658 kg and 1.8 m³, respectively, the density of the water is: Now, we can calculate the specific gravity:
Final Answer
The specific gravity of the composite is approximately 0.087.
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