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What is the most statistically landed-on property on a Monopoly board?
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Step 1:To solve this problem, we need to consider the properties in a standard Monopoly board and calculate the probability of landing on each property.
There are 40 properties in total, including 22 streets, 2 railroads, 2 utilities, and 14 tax spaces and chance/community chest cards.
Step 2:: Calculate the probability of landing on a street.
P(street) = \frac{22}{40} = \boxed{\frac{11}{20}}
There are 22 streets on a Monopoly board. Since there are 40 properties in total, the probability of landing on a street is:
Step 3:: Calculate the probability of landing on a railroad.
P(railroad) = \frac{2}{40} = \boxed{\frac{1}{20}}
There are 2 railroads on a Monopoly board. The probability of landing on a railroad is:
Step 4:: Calculate the probability of landing on a utility.
P(utility) = \frac{2}{40} = \boxed{\frac{1}{20}}
There are 2 utilities on a Monopoly board. The probability of landing on a utility is:
Step 5:: Calculate the probability of landing on a tax space or chance/community chest card.
P(tax \ or \ chance/community \ chest) = \frac{14}{40} = \boxed{\frac{7}{20}}
There are 14 tax spaces and chance/community chest cards on a Monopoly board. The probability of landing on a tax space or chance/community chest card is:
Final Answer
The most statistically landed-on property on a Monopoly board is a street, with a probability of \frac{11}{20}. The other properties with the highest probability are tax spaces or chance/community chest cards, with a probability of \frac{7}{20}.
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