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Find the point(s) on the surface at which the tangent plane is horizontal. z= 9−x 2 −y 2 + 8y (x,y,z)=(…)
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Answer

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Step 1
I'll solve this step by step, carefully following the LaTeX formatting guidelines:

Step 2
: Find the partial derivatives

\frac{\partial z}{\partial y} = -2y + 8
To find points where the tangent plane is horizontal, we need to find where the partial derivatives with respect to x and y are both zero. Partial derivative with respect to x: Partial derivative with respect to y:

Final Answer

The point where the tangent plane is horizontal is (0, 4, 25).