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Solution Manual for Advanced Semiconductor Fundamentals, 2nd Edition

Solution Manual for Advanced Semiconductor Fundamentals, 2nd Edition is the ultimate guide to solving textbook questions, offering easy-to-follow solutions.

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    Solutions Manual Volume VI Advanced Semiconductor Fundamentals Second Edition Robert F. Pierret Modular Series on Solid State Devices Gerold W. Neudeck * Robert F. Pierret Series Editors

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    Downloaded from StudyXY.com ® + StudyXY Sd Ye. o> \ | iF ’ pr E \ 3 S Stu dy Anything This ContentHas been Posted On StudyXY.com as supplementary learning material. StudyXY does not endrose any university, college or publisher. Allmaterials posted are under the liability of the contributors. wv 8) www.studyxy.com

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    Contents 1 Basic Semiconductor Properties 1-1 2 Elements of Quantum Mechanics 2-1 3 Energy Band Theory 3-1 4 Equilibrium Carrier Statistics 4-1 5 Recombination-Generation Processes 5-1 6 Carrier Transport 6-1 iii | Wy T= StudyXY

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    PROBLEM SoLurions Charrer L (1.1) @ Y | - ps 4 wo 7 don vatife 000 onlop and bellow facss & ib <+.7F atom along cach ventical ola od Total proks = axk vr uxt = 3 2®48,0,0,0, 4 Tor VIEW 29.8,0,0,0, oo plawe# 42494°,9,%, B ... plane #2 eo oe © 0... pluses? A A A A A A 2,9,0,0,°, «) bee (1.3) o @) The diamond] Lattice wa ompoand of Lu inlenpomelrating fee Laltiées, Each Fcc Latta cid cat covdains 4 aloms. Imapectiy Fig. l.5a Laaks To the Aamo conclusion -~ There ang 4 atoms [ally Cuacdle He celle ambd am Fcc (by 3 22 Si_pToms — ATomsfunercen E] —_ = 4.99%x00 a am a? (5431x108) 3 A 1.5 1-1

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    (c) Tovkiy at Fig. 1.Sa we mole that Tho wppos frou carmen Appa frond cern SV aon moighfats These axe anporstad by Vi x Louglll of a body dogouad Thay d =+t Fa = 13 (5 42ix10°) = 2.352 X10 em. ¥ 4 p—— (1.3) Jooliiy ot Fig. liba we conclude (covdiy (Qh alow wit Foye) + aod bollon/tap os Ee x6 = 1 afon Totsd wale ca82 owlap 6d bellow farsa AT conus we 4 atom aloo aX conduc of lop +hotlow fos .. THR of 3 odes ou lop + hollow fos ! ALSO Tara sua 3 stows Liselle 0000 masa meldlle of N por vant al Oo staked vithe tadk, the hosagonsd ud cad Uolisus 3F ak Nafows CHIE. SE SS — ona? REVERS 13 (3Au5x10°8) 2 (4.9798x 107°) = 4.790. x 102 = 1-2

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    (4) . . @) &) b,3, morwnis lol) udtaeapls We s,s... 1/Cirencerrd L233 LL Mocripy X 6 to got white muudieo (123) .... Mier Indices oF Pane Wh) [3] duwdier mormuslle plang has soma ondliia 04 plain’ cadre craplale (b) 2,00, 3 oo mormnllaged cdauapls Uo, Uz 1/1atencerts 3,°,2 eda 52 X & (302) ww. Hicew Lodies ©) rE adapts Ua odaangte already abate mobo (via) ... Mew Indices NoTE: hthtt 20) thes Tha A culo osmeidlal antl the a; opis asad bo 3. Thase cone maed (1.5) (a) Imlorcephs ... 1, 1,00 (6) Indloregls oo, 1,11 V/Imorcopha 1, 1,0 t/Iwdencopls ov. 11,1 whol #2at wo. 1,0 Who # act (0s 11,1 Mulan indices ... (110) Mon tndlicad vv, (111) © Projoelions 055 (@ Pood E Los allomg tho Wheto # set 1c 0,1, cube drbgona. Dueck... [oI1] Direction ... CU] 1-3

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    1.6 * H (6) | so hs A i ow * th) 2 2 hs 33 Y 3 5 9 Go x (c) x d) (1.7) (@) To Lia witha (100) senfuce ploma o eon macsat he perpercdienlon Zo the [100] Dinactesn. Ua E4,.(13) cn @ = ha , =O wohy=,ky=0, 270 (hy eke)" or hy = 0 Ths 000 daroeliaa [0RQT La wi theo (100) 2faro plas. Lottd, [oT [olT], [oTT] ... <1107 duaclisis Lying we ty (100) aufero plane (0) For a doveduin To ba parpocdieidar To Who [1117 diradas we mareat howe (warig Eq (1.3) a8 = hithky+& EY Ye {7 (heki) [Bay directo Lhiead cohue hitkat = 0] coiog be porpandicidod to Ya LT danadlagn. Fosacle answers a [031 , [373] ole 1-4

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    (1.8) ©) Gubic (b) Esamining Fig. 1.6, we concluds Wel there are Hf alems coho he did call, ( Thare ara Vi of (2 atoms adeng the cube edges 1 inlonier oem. © albvonetuiely, one mpl mete thal tha Pb and S alors Lie on oilaiprelisliy feo Lalivios, The foc Citleio has # olowy por cut a0.) tb atemut/om® = = it - 2 o 2 (533eaxi0E? 1.4122X10 Jom © 0. (120) plane hos vidorcapts of 1,5, amb 20 on the ry and 2 ales) respectively, of ne x a ~Pb stem aie] I dn oss] a “= 1 SdFgi V5a/2 Pb atoms/ow™ = lao - _2 ~~ _ M9 mame © Glial V5 (523669 ~ 5352x106 (1.9) @) Sf tha oavogs plosaca o CHD), ATH, (UT) on (ITT) plone wa = = » [eo = si.1¢7 | Ifthe Daourngs plana 6 a (T10), (TU), (T(T) wc (TT) plone we = + = le = 125.26° | OeSualllyy 02 tfomad Fig. PLY, both of tha above cde Sad ASR ERA AA owned poudiiy dpm ova hes a mowed poiatiiy dewd. 1-5

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    (0) Fow, procs (eat). ( Nye Aang pac {aes (IT, G0T), (TT1) a (THT) anime plone (©) Go Auscersned wm tha Zant | a (100) pls.a thse prusmeny Yt oom tha ge dip a (010 plone. The tmTarrept of * fiud plowa aulth (160) plo alvsge a <ilo> Loacduse, Thus —p [ow] (0) To dabenmnia tha poseFionsiy of the eget for souring, wre moist dalorwiio tha amgles doe foe nad awd [11074 [12] LDuaelioua, Fon [oot] [112] C = _d = ° [2 oN) ad = OG = 35.26 For [07 += [137 = A poe B [F25Y Tia =» 6 = SHT4 “9 we. dee the memual To the sen rr ag (tel RN & 1-6

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    PRORLEN SOLUTIONS Chrpree 2 (21) Wa conalicdad fron lhe Lot alow smalyscs that [3 = MeL 30 Eo" trent © 7 ar oY [Eyal Thes £ am edelon inthe m=1 atato [2 Ea = 8% 1 me) ev A (krkge i)? Ks =-0.0488 eV — (2) Wa haow E = Tomy? P = my = — : __h A= bp Mame or pg Thos E = Loy? = e = ht he Am, "Jw, @damB) 2 _ (e.e3xt0™? 2 | Lt = ( ww? =r) 2(3.x1073") lexi Ceomests To eV E = 435 keV —_— 2-1

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    (2.3Ya) Using Ey. (2:13) 0nd Table 2.1 coe conclude a = + hal < Pr | Po z Fa [+] max wi = Yh = Ayam To Yo oop puerSE Thos * SO VE PERCE ° MIT a ft w= REx ey =a x] ex mu ° . mI por = mt \igemyay ALE ex x ° ° NCE (6) Guem §, = Ayo TE . a x we require § rude = wif inlose) 5x =| Io) [ed ” = nr aa wu @ : Telling X= ow k w poder grate * " Ae Le _ 4, ~ IA Far — a 2 Ay Mu = 59% = Hi (5 poms) = Wale = ZA! o Thus N a Ww, == x hose 2-2

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    (© Referring lo Eg (3.18) ord) Table 21, we conclude a a a <= {Wand < [Rn cintogpges - 3 vaitemga 0 (] 0 NI dat y= Nr = dy = neds y, Nr a Ne ar = guia SAE CRE SN 0 a a @1) Thaw mumber of wwoaysle This protlm. rg i Me = E/U, £0.01, yg) = ee ©-al§ £-0a al solutions therefore fo onthe Lower negative) 2egmend the Feq. 2.7 F(X) plot ome to §20 f(g) =0. A Sh jo] ae sy ee Ton rhb a Large pvnben of Bee between 5 =0 amd] §=o0.00 fhe Jan fen leon to alent vertical as of cova the §- sof Ye Fig. 27 plot. We to The Spi ocd toc, andthe victercapts onthe FY) conve, covnsspodivg [othe finch ell 2-3

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    (2.5) (a) Equations To he Aotvd 2 dh tk = 0 k = famEM . -afa4z20la dpe —ape = 0 o =m BE reg; 5 o - poo = pe +e" re Y= P,atwkr + Bonk wd «x2 pw = Ae vee EES Ye) =0 ) Y (+e0) =0 AS EIE FAC EAE dol ap. AB 4 Lla-tblsr oly, (6) (l-w) =O nogrismas B.=0 fs) 20 roguind Ay =0 Co Lwro-ing Yi-%) =*+ Yr) mthe ~af> <x «ala ragton yells Ay, sume) + Bo con (-ha) = + A, stinky * B, coe kz ot =Rysakx +B, cot kx = XA 4mbrE By conlex amd ~ARobmkr=0 = Ry =0 J oven parity 1B, cexkr=0 == B,=0 4 0d) pana Ym = ae Vota) = Po cour cub EE Pele) = BEF 24

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    © Appligung Ue cotinirly boundary condos guolds CUE PARITY —ODD PARITY res pte he = punks ® ) dal “he “Be pkg pine oh € 2 eh, 052 ® 8, cok = ge” Aybinhe = pe ® . ~olaf: B7.7EY —kB amt =-clB kp ce kl =~ € ® Combing either 2auation © oni A @ and ® we conclude “- { k ton BE oven poly ke cot BE ov 0 parity (4) Eg. (2.435) noalls lanka = 25K , ot lading The HINT Alan (kala) _ dak _ ole _ Lenka = TT Akain Cad © {dR = iy Po Alsmlkala) = [ = Ttameala)]/8 Lom? (kaf~) + 2¥ lamlRah) —| = 0 «= Relies co taatkal) = yt [ 31" _itedePr =a) fl HRT 1 TT but Ye = [Ee [+1 = lo] = [=] thus [loft] [Le (fe) afk. @Inest tan ig =~ TR I#] Jade | {i nest ame as partic) result 25

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    (3.6) (0) Berowsa the poleulial U inginide 250, we moed to dead with the law hogton Le awd only ad +k =o k = Vame/s? ww 0<x<a acd ai =0 of 22m... xra (b) The gemersl detubions , (dodscdl To Egn(2.336 oud <) inthe tent, ane Uhr) = Paimkr +Bycotkr 0 <xla pn = Ae "vB e™ axra ©) The appropiate boundary conditions ara $0) =0 3 Yk) =0 - | 10) ya) = ge) | el 2h @) Opplicalion of the bovudiorg colddsn Yall B, = 0 3 Ay =0 Podinka = 8,67; kiyeuka =-lB,€ @ Dividing the Lefthan) oqualioi abore by Teo naghit-howd) equals yal lamka = —or or E [ taka =-& = Vee ] 26

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    GM@) Forlhe specead protlom Eq.(2 (6) dumpliflis Lo a + Tr E-ax)p =0 Jones (Ey) = IE((~L) = RU-E) we com undo Th rl-£1p =o x30 () © Yr=0 atz=o0 D w=0 al x zoo © YW at x =x, ConTiwLTYy ® oe Fad ad r=ke keQu(ResenTs x «© oe By conta coll he vfonile ud fruits poloidal wed 9 pl aha Sy Be ie GE conticnng AF EE va pO ar Pa x 7 Xe Spcoatr=o (® Fligge wliesto, @ gamansl solution of the oom (sstiafusy Fad aa x2) of . Ys) = LAR) Somali co Jad AL a Quny fuses : “3 oo momsliyD positaar, Comparing Fliigae anh) oun metotbion woe conclude 3. T=) (f -0) 2-7

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