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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Document preview page 1

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Solution Manual for Machine Elements in Mechanical Design, 6th Edition

Solution Manual for Machine Elements in Mechanical Design, 6th Edition is an essential tool for mastering your textbook, offering detailed solutions and helpful explanations.

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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 1 preview imageSolution ManualForMACHINE ELEMENTSIN MECHANICAL DESIGNSixth EditionRobert L. Mott,University of DaytonEdward M. Vavrek,Purdue UniversityJyhwen Wang,Texas A&M University
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 2 preview image
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 3 preview imageiiiTable of ContentsChapter1TheNatureofMechanicalDesign1Chapter2MaterialsinMechanicalDesign3Chapter3StressandDeformationAnalysis11Chapter4CombinedStressesandStressTransformations50Chapter5DesignforDifferentTypesofLoading121Chapter6Columns158Chapter7BeltDrives,ChainDrivesandWireRope178Chapter8KinematicsofGears193Chapter9SpurGearDesign225Chapter10HelicalGears,BevelGearsandWormgearing275Chapter11Keys,Couplings,andSeals311Chapter12ShaftDesign316Chapter13TolerancesandFits354Chapter14RollingContactBearings360Chapter16PlainSurfaceBearings365Chapter17LinearMotionElements372Chapter18Springs377Chapter19Fasteners396Chapter20MachineFrames,BoltedConnectionsandWeldedJoints398Chapter21ElectricMotorsandControls407Chapter22MotionControl:ClutchesandBrakes411
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 4 preview image1CHAPTER1THENATUREOFMECHANICALDESIGNProblems 1‐14 require the specification of functions and design requirements for designprojects and have no unique solutions.15.D ൌ 1.75 in25.4 mm/in ൌ 44.5 mm16.L ൌ 46.0 m0.3048 m/ft ൌ 14.0 m17.T ൌ 12 500 lbin0.1130 Nm/lbin ൌ 1418 Nm18.A ൌ 4.12 in2645.2 mm2/in2ൌ 2658 mm219.Section modulus ൌS ൌ 14.8 in31.639104mm3/in3ൌ 2.43105mm320.Moment of inertia ൌI ൌ 88.0 in44.162105mm4/in4ൌ 3.66107mm421.Given:Aminൌ 750 mm2: In U.S. units;Aminൌ 1.162 in2U.S. Angle – From Appendix 15‐1:L223/8;A ൌ 1.36 in2ሾ890 mm2SI Angle – From Appendix 15‐3: Angle 75755;A ൌ 864 mm222.Power ൌP ൌ 7.5 hp745.7 W/hp ൌ 5.59103W ൌ 5.59 kW23.Ultimate tensile strengthsuൌ 127 ksi6.895 MPa/ksi ൌ 876 MPa24.Given: Steel shaft;D ൌ 35 mm ൌ 0.035 m;L ൌ 675 mm ൌ 0.675 mFind: Weight of the shaft: Weight ൌ massg ;g ൌ 9.81 m/s2Mass ൌ densityvolume; Density of steel ൌ 7680 kg/m3ሾFrom Appendix 3ሿVolume ൌV ൌ arealength ൌD2/4LV ൌሺ0.035 mሻ2/40.675 m ൌ 6.4910‐4m3Mass ൌ 7680 kg/m36.4910‐4m3ൌ 4.98 kgWeight ൌmg ൌ 4.98 kg9.81 m/s2ൌ 48.9 kgm/s2ൌ 48.9 N
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 5 preview image225.Given: For a torsional spring, Torque ൌ 180 lbin for 35of rotation.Find the scale of the spring ൌ Torque per unit of rotation. Express the result in bothU.S. and SI units.T ൌ 180 lbin0.1130 Nm/lbin ൌ 20.3 NmAngle ൌ ࣂ ൌ 35rad/180ൌ 0.611 radiansScale ൌT/ࣂ ൌ 180 lbin/35ൌ 5.14 lbin/degreeScale ൌT/ࣂ ൌ 20.3 Nm/0.611 rad ൌ 33.3 Nm/rad26.Given: 12.5 hp motor operating 16 h/day, 5 days/weekCompute the energy,E, used by the motor for one year in both U.S. and SI units.E ൌ 12.5 hp16h/day5 days/wk52 wks/year550 ftlb/s/hp3600 s/hE ൌ 1.031011ftlb/yearE ൌ 1.031011ftlb/year1.356 J/ftlb1.0 Nm/J1.0 W/Nm/s1h/3600 sE ൌ 38.8106Wh/year ൌ 38.8 MWh/year27.Given: Viscosity ൌൌ 3.75 reynሺ1.0 lbs/in2ሻ/reyn144 in2/ft2ൌ 540 lbs/ft2ൌ 3.5 lbs/in24.448 N/lb1.0 in2/645.2 mm2106mm2/m2ൌ 25.9103Ns/m228.Given:n ൌ 1750 rpm; 24h/day; 5.0 years. Find life in number of revolutions.Life ൌ 1750 rev/min24 h/day60 min/h365 days/year5 yearsLife ൌ 4.60109revolutions
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 6 preview image3From Eq. 2-5:
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 7 preview image4߶217)17)SAE(Table 2-8)(Table 2-9)SAEfrom SAE 1040, 4140, 4340, 4640(Table 2-9)from SAE 1040, 4140, 4340, 4640steels(Table 2-9)SAE 1080 steel is a reasonable choice.SAE 5160 OQT 1000
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 8 preview image5SAE 1040 WQTSAE 1040 andSAE 1040 WQTSAE 1040 andSAE 1015, 1020,[See Appedix A-5.]ASTM A992 Structural steel is used for mostwide-flange beam shapes.
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 9 preview image6Problem 38 (Continued)ASTM A536, Grade 100-70-03 is a ductile iron with atensile strength of 100 ksi (689 MPa); a yield strength of70 ksi (483 MPa); 3% elongation (brittle); modulus ofelasticity (stiffness) of 24x106psi (165 GPa).ASTM A47, Grade 32510 is a malleable iron with a tensilestrength of 50 ksi (345 MPa); a yield strength of 32.5 ksi(224 MPa); 10% elongation (ductile); modulus of elasticity(stiffnes) of 26x106(179 GPa.(Table 2-11)Aluminum 7178-T6 has the highest strength; tensile strength =88 ksi (607 MPa); yield strength = 78 ksi (538 MPa).
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 10 preview image7PET, polyurethanePET.PETResins used for composites include polyesters, epoxies,polyimides, phenolics, (all thermosets), andthermoplastics: PE, PA, PEEK, PPS, PVC.
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 11 preview image8See Section 2-17, Table 2-16, Figures 2-23 and 2-24 foranswers to Questions 74 to 100.Questions 70-73 refer to Figure 2-23 and Table 2-17 in the text.General conclusions from Questions 70-73: The specificstrengths of the metals listed range from 0.194x106to1.00x106, approximately a factor of 5.0. The specificstiffnesses are very nearly equal for all metals listed,approximately 1.0x108in. The specific strengths of thecomposites listed range from 1.87 to 4.88x106in, muchhigher than any of the metals. Glass/epoxy has a specificstiffness about 2/3 that of the metals. The othercomposites listed range from 2.2 to 8.3 times as stiff asthe metals.
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 12 preview image9
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 14 preview image11CHAPTER 3STRESS AND DEFORMATION ANALYSISDirectTensionandCompression1.;ܣ/ܨ ൌ ߪ ܣൌ ߨሺ18െ 12ሻ/4 ൌ ૚૝૚. ૝ ܕܕ ߪൌ 4500 N/141.4 mmൌ 31.8 N/mmൌ ૜૚. ૡ ܉۾ۻൌ ߜ௉௅ா஺ሺସହ଴଴ ୒ሻሺ଻ହ଴ ୫୫ሻሺଶ଴଻ൈଵ଴୒/୫୫ሻሺଵସଵ.ସ ୫୫ଵ଴୫୫ൌ ૙. ૚૛ ܕܕ2. ߪൌ ܣ/ܨൌ 3500 N/ሺߨሺ10ሻ/4 ሻ mmൌ ૝૝. ૟ ܉۾ۻ3. ߪൌ ܣ/ܨൌ 20 ൈ 10N/ሺ10 ∙ 30ሻ mmൌ ૟૟. ૠ ܉۾ۻ4. ߪൌ ܣ/ܨൌ 860 lb/ሺ0.40 ܑ݊݅ܛܘ ൌ ૞૜ૠ૞5. ߪൌ ܣ/ܨൌ 1900 lb/ሺߨሺ0.375 ݊݅/4ሻ ൌ ૚ૠ ૛૙૙ ܑܛܘ6.;ܣ/ ܲൌ ߪൌ ܣ݉݉ ሺ12ൌ 144 mm; ߪൌ 5000 N/144 mmሻܔܔۯሺ ܉۾ۻ ૠ .ൌ ૜૝ൌ ߜ௉௅ா஺ሺହ଴଴଴ ேሻሺଵ଺ହ଴ ௠௠ሻሺா ே/௠௠ሻሺଵସସ ௠௠ହ଻ ଶଽଶmma)SAE 1020; ܧൌ 207 GPa ൌ 207 ൈ 10N/mm; ࢾ ൌ ૙. ૛ૠૠ ܕܕb)SAE 8650; ܧൌ 207 GPa; ࢾ ൌ ૙. ૛ૠૠ ܕܕc)Ductile iron A536(60-40-18); ܧൌ 165 GPa;ࢾ ൌ ૙. ૜૝ૠ ܕܕd)Aluminum 6061-T6; ܧൌ 69 GPa; ࢾ ൌ ૙. ૡ૜૙ ܕܕe)Titanium Ti-6AL-4V; ܧൌ 114 GPa;ࢾ ൌ ૙. ૞૙૜ ܕܕf)PVC;Tensile Modulus ൌ ܧൌ 2410 MPa ൌ 2410 N/mm;ࢾ ൌ ૛૜. ૡ ܕܕg)Phenolic; ܧൌ 7580 MPa;ࢾ ൌ ૠ. ૞૟ ܕܕNote: The stress is close to the ultimate for f and g.
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 15 preview image127.ܲ;ܣܧ/ܮ ܲൌ ߜఋா஺ ܣൌ ሺ2.25െ 2.01ሻ inൌ ૚. ૙૛ ܑ ܖܲሺ଴.଴଴ସ ୧୬ሻ൫ଵ଴ൈଵ଴୪ୠ/୧୬൯൫ଵ.଴ଶ ୧୬ଵ଺.଴ ୧୬ൌ ૛૞૞૟ ܊ܔ ߪൌ ܣ/ ܲൌ 2556 lb/1.02 inܑܛܘ ൌ ૛૞૙૟8. ܨൌ 2500 lb;ܯΣൌ 0 ൌ 2500ሺ75ሻ െ ܨሺ60ሻܨൌ 2500ሺ75/60ሻ ൌ 3125 lb ൌ Tensile force in ܥܣൌ ߪଷଵଶହ ୪ୠሺଵ.ହ଴ሻሺଷ.ହ଴ሻ ୧୬ܑܛܘ ൌ ૞ૢ૞9.ܨ2 ߠ ݊݅ݏൌ 1500 lbܨൌ 1500/ሺ2 ݊݅ݏሺ45°ሻሻ ൌ ૚૙૟૚ ܊ܔ10.;ܣ/ ܲൌ ߪRequired ܣൌܲ /ߪ௔௟௟௢௪ൌ ܣଵ଴଺ଵ ୪ୠଵ଼ ଴଴଴ ୪ୠ/୧୬ൌ 0.0589 inܦߨ ൌ/4 ܦൌ ටସ஺ൌ ටସሺ଴.଴ହ଼ଽ ሻൌ ૙. ૛ૠ૝ ܑ ܖܕܝܕܑܖܑܕ11. ߠൌ 15°;ܨଵହ଴଴ ௟௕ଶ ௦௜௡ ఏଵହ଴଴ ௟௕ଶ ௦௜௡ሺଵହሻൌ 2898 lb ܣൌ 2898/18 000 ൌ 0.161 in; ࡰൌ ට૝ሺ૙.૚૟૚ሻ࣊ൌ ૙. ૝૞૜ ܑ ܖ2.25 in2.01 in506075ܨܨߠ ܨൌ 1500 lbܨABC
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Solution Manual for Machine Elements in Mechanical Design, 6th Edition - Page 16 preview image1312.Joint BJoint AStresses:AB, BC:ߪ஺஻ߪ ൌ஻஼ଽ.଴ଽൈଵ଴ሺଵଶሻሺଷ଴ሻ ௠௠ൌ ૛૞. ૜ ܉۾ۻܖܗܑܛܖ܍܂BD:ߪ஻஽ଵ଴.ହൈଵ଴ሺଶሻሺଵ଴ሻሺଷ଴ሻ ௠௠ൌ ૚ૠ. ૞ ܉۾ۻܖܗܑܛܖ܍܂AD, CD: ܣൌ ሺ30ሻെ ሺ20ሻൌ 500 mmߪ஺஽ߪ ൌ஼஽ൌିଵ଴.ହൈଵ଴ହ଴଴ ௠௠ൌ െ૛૚. ૙ ܉۾ۻܖܗܑܛܛ܍ܚܘܕܗ۱13.Figure P3‐13ܯΣൌ 0 ൌ 6000ሺ6ሻ ൅ 12 000ሺ12ሻ െܴிሺ18ሻܴிൌ 10 000 lbܯΣிൌ 0 ൌ 12 000ሺ6ሻ ൅ 6000ሺ12ሻ െܴሺ18ሻܴൌ 8000 lbNote: sin= 8/10 = 0.80; cos= 6/10 = 0.60ܣܤܥܤܤܣܦܣ30°ܣܤ5.25 kN5.25 kN10.5 kN5.2530°30°ܣܦܥܤ10.5 kN ܦܤൌ 10.5 kNߠ6ߠߠߠ1866600012 00088ܣܴܴி10ܤܥܦܧܨADsin 30= 5.25 kNAD= 10.5 kN =CDAB = ADcos 30= 9.09 kN =BC
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