A Comprehensive Guide To Polynomial Operations, Coordinate Geometry, And Mathematical Simplification
- Mathematics
- 10 pages
- Shared May 2025
Simplify your math studies with this detailed Homework Solution.
Preview 4 of 10 pages
See the first 4 pages exactly as they appear in the document.
Page 1 Read page 1 as text
A Comprehensive Guide to Polynomial Operations, Coordinate Geometry, and Mathematical Simplification Polynomials and Mathematical Simplification: A Step - by - Step Approach (10x + 12) + (6x + 10) add the polynomial Let's break down the given expression step by step: Given: (10x+12)+(6x+10)(10x + 12) + (6x + 10) Step 1: Remove the parentheses Since there are no negative signs outside the parentheses, we can directly combine the terms inside the parentheses. 10x+12+6x+1010x + 12 + 6x + 10 Step 2: Combine like terms Now, group the like terms (terms involving xx and constant terms): • Combine the xx - terms: 10x+6x=16x10x + 6x = 16x • Combine the constants: 12+10=2212 + 10 = 22 Step 3: Write the simplified result So, the simplified expression is: 16x+2216x + 22 Final Answer: 16x+2216x + 22 2. Subtract the polynomial Let's break down the given expression step by step: Given: (11x2+7x+11)−(11x2+20x+12)(11x^2 + 7x + 11) - (11x^2 + 20x + 12) Step 1: Distribute the negative sign
Page 2 Page 3 Read page 3 as text
Distribute the negative sign across the second set of parentheses: 11x2+7x+11−11x2−20x−1211x^2 + 7x + 11 - 11x^2 - 20x - 12 Step 2: Combine like terms Now, group the like terms (terms involving x2x^2, xx, and constants): • Combine the x2x^2 - terms: 11x2−11x2=011x^2 - 11x^2 = 0 • Combine the xx - terms: 7x−20x=−13x7x - 20x = - 13x • Combine the constant terms: 11−12=−111 - 12 = - 1 Step 3: Write the simplified result So, the simplified expression is: −13x−1 - 13x - 1 Final Answer: −13x−1 - 13x - 1 3. Simplify Let's simplify 12×14412 \ times \ sqrt{144}. Step 1: Find the square root of 144 144=12 \ sqrt{144} = 12 Step 2: Multiply by 12
Page 4 Read page 4 as text
12×12=14412 \ times 12 = 144 Final Answer: 144144 4. Find the distance between P and Q using the distance formula P( - 3,8) and Q(5,8) To find the distance between the points P(−3,8)P( - 3, 8) and Q(5,8)Q(5, 8) using the distance formula, we'll follow the steps below: Distance Formula: The formula is: d=(x2−x1)2+(y2−y1)2d = \ sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} Where: • (x1,y1)(x_1, y_1) is the first point (P), • (x2,y2)(x_2, y_2) is the second point (Q). Step 1: Identify the coordinates of points P and Q • P(x1,y1)=(−3,8)P(x_1, y_1) = ( - 3, 8) • Q(x2,y2)=(5,8)Q(x_2, y_2) = (5, 8) Step 2: Plug the coordinates into the distance formula Now substitute the values of x1x_1, y1y_1, x2x_2, and y2y_2 into the formula: d=(5−(−3))2+(8−8)2d = \ sqrt{(5 - ( - 3))^2 + (8 - 8)^2} Step 3: Simplify the terms First, simplify inside the parentheses:
6 more pages in the full document
Unlock it once and it stays in your library, ready to chat with or turn into flashcards.
Unlock the full documentMore Mathematics study materials
See all
Exam GuidesTest Bank for Precalculus, 6th Edition
Mathematics
1051 pages175downloadsFeb 2025
Textbook GuidesSolution Manual For Introduction To Management Science, 11th Edition
Mathematics
437 pages167downloadsFeb 2025
Textbook GuidesSolution Manual For Derivatives Markets, 3rd Edition
Mathematics
358 pages143downloadsFeb 2025
Textbook GuidesSolution Manual for Geometry, 1st Edition
Mathematics
446 pages141downloadsFeb 2025
Textbook GuidesSolution Manual for Beginning Algebra, 7th Edition
Mathematics
479 pages139downloadsFeb 2025
Textbook GuidesSolution Manual for Developmental Mathematics, 1st Edition
Mathematics
1623 pages137downloadsFeb 2025
Textbook GuidesSolution Manual for Elementary and Intermediate Algebra: Graphs and Models, 5th Edition
Mathematics
1278 pages126downloadsFeb 2025
Exam GuidesTest Bank for Calculus: Concepts and Contexts, Enhanced 4th Edition
Mathematics
687 pages122downloadsFeb 2025
Study this document with CramX
Once it is in your library, every tool can work from it.

