Advanced Series And Recurrence Relations: Applications Of Faulhaber's Formula And Generating Functions
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Advanced Series and Recurrence Relations: Applications of Faulhaber's Formula and Generating Functions Q3) π π = 6 π π β 1 β 8 π π β 2 π π + 2 = 6 π π + 1 β 8 π π β π π + 2 π₯ π β π = 0 = 6 β π π + 1 π₯ π β π = 0 β 8 β π π π₯ π β π = 0 β π π π₯ π β 2 β π = 2 = 6 β π π π₯ π β 1 β π = 1 β 8 β π π π₯ π β π = 0 β π π π₯ Β² π₯ π β π = 2 = 6 β π π π₯ π₯ π β π = 1 β 8 β π π π₯ π β π = 0 Therefore if we have ( π₯ ) = β π π π₯ π β π = 0 : 1 π₯ Β² β π π π₯ π β π = 0 β π 0 π₯ Β² β π 1 π₯ π₯ Β² = 6 π₯ β π π π₯ π β π = 0 β 6 π 0 π₯ β 8 β π π π₯ π β π = 0 1 π₯ Β² π β 1 π₯ Β² β 2 π₯ = 6 π₯ π β 6 π₯ β 8 π Therefore : ( 1 π₯ Β² β 6 π₯ + 8 ) π = 1 π₯ Β² + 2 π₯ β 6 π₯ = 1 π₯ 2 β 4 π₯ π ( π₯ ) = 1 π₯ 2 β 4 π₯ 1 π₯ Β² β 6 π₯ + 8 = 1 β 4 π₯ 1 β 6 π₯ + 8 π₯ Β² Q4) 0 5 + 1 5 + β― + π 5 = β π 5 π π = 0 This sum can be approximated by the Faulhaber formula : β π π = 1 π + 1 ( π π + 1 + 1 2 ( π + 1 ) π π + 1 6 ( π + 1 2 ) π π β 1 β 1 30 ( π + 1 4 ) π π β 3 + 1 42 ( π + 1 6 ) π π β 5 π π = 1 + β― ) In this case p = 5 :
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