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Algebra Test: Linear Equations, Graphs, and Systems of Equations

A test focusing on solving linear equations, graphing equations, and solving systems of equations in algebra.

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    Algebra Test: Linear Equations, Graphs, and Systems of Equations Class: Algebra 1 Part 2 U1 Mid Report Date: 02/26/2013 Print Test Questions 1. Find the slope of the line. A. 1 B. 0 C. 2 D. Points Possible:0.47 2. Find the x - and y - intercept of the line. 2 x + 3 y = – 18 A. x - intercept is 18; y - intercept is 18. B. x - intercept is – 6; y - intercept is – 9. C. x - intercept is 2; y - intercept is 3. D. x - intercept is – 9; y - intercept is – 6. Points Possible:0.47 3. Find the slope and y - intercept of the line.

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    y = x + 1 A. ; – 1 B. – 1; C. ; 1 D. 1; Points Possible:0.47 4. Write an equation of a line with the given slope and y - intercept. m = , b = A. y = x – B. y = x – C. y = x + D. y = x + Points Possible:0.47 5. Use the slope and y - intercept to graph the equation. y = x + 4 A.

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    B. C. D.

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    Points Possible:0.47 6. Match the equation with its graph. – 6 x – 4 y = 24 A. B. C.

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    D. Points Possible:0.47 7. A line passes through (3, – 2) and (8, 2). a. Write an equation for the line in point - slope form. b. Rewrite the equation in standard form using integers. A. y + 2 = ( x + 3); – 4 x + 5 y = – 22 B. y – 3 = ( x + 2); – 4 x + 5 y = 23 C. y – 2 = ( x – 3); – 4 x + 5 y = 22 D. y + 2 = ( x – 3); – 4 x + 5 y = – 22 Points Possible:0.47 8. The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation.

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    Time (days) Cost ($) 3 75 4 100 5 125 6 150 A. dollars per day; the cost is $25 for each day. B. dollars per day; the cost is $25 for each day. C. dollars per day; the cost is $75 for each day. D. dollars per day; the costs $1 for 150 days Points Possible:0.47 9. State whether the slope is 0 or undefined. A. 0 B. undefined Points Possible:0.47 10. State whether the slope is 0 or undefined.

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    A. undefined B. 0 Points Possible:0.47 11. Use the graph. a. Which plant was the tallest at the beginning? b. Which plant had the greatest rate of change over the 6 weeks? A. plant 2; plant 2 B. plant 1; plant 3 C. plant 3; plant 1

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    D. plant 3; plant 3 Points Possible:0.47 12. Write y = x + 9 in standard form using integers. A. – x – 4 y = 36 B. – x + 4 y = 9 C. 4 x – y = 36 D. – x + 4 y = 36 Points Possible:0.47 13. Write y = x + 3 in standard form using integers. A. – 2 x + 3 y = 9 B. – 2 x + 3 y = 3 C. 3 x – 2 y = 9 D. – 2 x – 3 y = 9 Points Possible:0.47 14. Is the relationship shown by the data linear? If so, model the data with an equation. x y 3 2 9 7 15 12 21 17 A. The relationship is linear; y – 2 = ( x – 3). B. The relationship is linear; y – 3 = ( x – 2). C. The relationship is linear; y – 2 = ( x – 3). D. The relationship is not linear. Points Possible:0.47 15.

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    The table shows the height of a plant as it grows. a. Model the data with an equation. b. Based on your model, predict the height of the plant at 12 months. Time (months) Plant Height (cm) 3 24 5 40 7 56 9 72 A. y – 24 = ( x – 3); 48 cm B. y – 24 = 8( x – 3); 96 cm C. y – 3 = ( x – 24); 84 cm D. The relationship cannot be modeled. Points Possible:0.47 16. Find the slope of the line. A. B. C. D. Points Possible:0.47 17. Write an equation of a line with the given slope and y - intercept. m = 1, b = 4

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    A. y = 4 x + 1 B. y = x – 4 C. y = – 1 x + 4 D. y = x + 4 Points Possible:0.47 18. Find the slope of the line that passes through the pair of points. (1, 7), (10, 1) A. B. C. D. Points Possible:0.47 19. Giselle pays $240 in advance on her account at the athletic club. Each time she uses the club, $15 is deducted from the account. Model the situation with a linear function and a graph. A. b = 240 – 15 x B.

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    b = 240 + 15 x C. b = 225 + 15 x D. b = 225 – 15 x Points Possible:0.94 20. Find the x - and y - intercept of the line.

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    – 3 x – 2 y = 12 A. x - intercept is – 6; y - intercept is – 4. B. x - intercept is – 4; y - intercept is – 6. C. x - intercept is – 2 ; y - intercept is – 3. D. x - intercept is – 3; y - intercept is – 2. Points Possible:0.47 21. The grocery store sells kumquats for $4.75 a pound and Asian pears for $3.75 a pound. Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $12. A. 4.75 k = 3.75 p + 12 B. 4.75 k + 3.75 p = 12 C. 4.75 p + 3.75 k = 12 D. 4.75 + 3.75 = k Points Possible:0.47 22. The grocery store sells kumquats for $4.50 a pound and Asian pears for $2.50 a pound. Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $12. A. 4.5 + 2.5 = k B. 4.5 p + 2.5 k = 12 C. 4.5 k = 2.5 p + 12 D. 4.5 k + 2.5 p = 12 Points Possible:0.47 23. Write an equation in point - slope form for the line through the given point with the given slope. (4, 3); m = A. y + 3 = ( x + 4) B. y – 4 = ( x – 3) C. y + 3 = ( x – 4) D. y – 3 = ( x – 4)

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    Points Possible:0.47 24. A line passes through ( – 10, 3) and ( – 7, 10). a. Write an equation for the line in point - slope form. b. Rewrite the equation in standard form using integers. A. y – 3 = ( x – 10); – 7 x + 3 y = 79 B. y + 3 = ( x + 10); – 7 x + 3 y = – 79 C. y – 3 = ( x + 10); – 7 x + 3 y = 79 D. y + 10 = ( x – 3); – 7 x + 3 y = – 51 Points Possible:0.47 25. The table shows the height of a plant as it grows. a. Model the data with an equation. b. Based on your model, predict the height of the plant at 12 months. Time (months) Plant Height (cm) 3 9 5 15 7 21 9 27 A. y – 3 = ( x – 9); 39 cm B. y – 9 = 3( x – 3); 36 cm C. y – 9 = ( x – 3); 18 cm D. The relationship cannot be modeled. Points Possible:0.47 26. Find the slope and y - intercept of the line. 18 x + 2 y = – 36 A. 18; – 36 B. ; C.

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    ; D. ; Points Possible:0.47 27. The grocery store sells kumquats for $3.75 a pound and Asian pears for $2.25 a pound. Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $22. A. 3.75 p + 2.25 k = 22 B. 3.75 k + 2.25 p = 22 C. 3.75 + 2.25 = k D. 3.75 k = 2.25 p + 22 Points Possible:0.47 28. A line passes through ( – 5, – 3) and ( – 3, – 2). a. Write an equation for the line in point - slope form. b. Rewrite the equation in standard form using integers. A. y – 3 = ( x + 5); – x + 2 y = 1 B. y + 3 = ( x – 5); – x + 2 y = – 1 C. y + 5 = ( x + 3); – x + 2 y = – 7 D. y + 3 = ( x + 5); – x + 2 y = – 1 Points Possible:0.47 29. In April, you have a balance of $75 in your bank account. Each month you deposit $25. Let January = 1, February = 2, and so on. Write an equation for this situation. Use the equation to find the balance in June. A. y = 25( x – 4); $50 B. y – 75 = 25( x – 4) ; $125 C. y – 75 = 25 x ; $25 D. y = 25( x – 4); $75 Points Possible:0.47 30. Is the relationship shown by the data linear? If so, model the data with an equation.

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    x y 9 – 5 12 – 6 15 – 7 18 – 8 A. The relationship is not linear. B. The relationship is linear; y + 5 = ( x – 9). C. The relationship is linear; y – 9 = ( x + 5). D. The relationship is linear; y + 5 = ( x – 9). Points Possible:0.47 31. The table shows the height of a plant as it grows. a. Model the data with an equation. b. Based on your model, predict the height of the plant at 12 months. Time (months) Plant Height (cm) 3 18 5 30 7 42 9 54 A. y – 18 = ( x – 3); 36 cm B. y – 18 = 6( x – 3); 72 cm C. The relationship cannot be modeled. D. y – 3 = ( x – 18); 66 cm Points Possible:0.47 32. A line passes through (6, – 9) and (10, – 2). a. Write an equation for the line in point - slope form. b. Rewrite the equation in standard form using integers. A. y – 9 = ( x – 6); – 7 x + 4 y = 78 B. y – 6 = ( x + 9); – 7 x + 4 y = 87 C.

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