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MATH 1324 Homework 12 Answers

Homework 12 for MATH 1324 Finite Math covers problems from Section 7.3. Multiple-choice answers for problem 8b and 10b are provided. Select the correct values to practice and test your understanding of the concepts in the section.

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    1 MATH 1324 - Finite Math with Applications Homework 12 (Untimed, 1 Attempt) DUE November 25, 2022 11:59:00 PM! QI. The choices for problem number 8 part b, from Section 7.3 in the book are given below. * A. 6.9676 * B. 2.6396 * C. 4.5727 * D. 4.8776 * E. 8.0278 * F. None of the above. * x___________ I - 3 - 1 1 3 5 P(X = xj | 0.17 0.28 0.15 0.27 0.13 * Part B: Find the variance. * E X = x 1 p. + x 2 p 2 + x 2 p 2 = - 3 : 0 . 1 7 -11'0.28 1 0.15 + 3 '0.27' + 5' 0.131 = 0.82 = p * Vor A’ = p. x x — | Z + p 2 l x, - p 2+ p 2 = 0.17(-3 - 0.82) 2 + 0.28(-l - 0.82) 2 + 0.15(1 - 0.82) + 0.27(3 - 0.82) 2 + 0.13(5 - 0.82) 2 = 6.9676 Q2. The choices for problem number 10 pan b, from Section 7.3 in die book are given below T . * A. 312.4215 * B. 284.8275 * C. 248.9658 * D. 298.9746 * E. 315.9872 * F. None of the above. * x | 0 15 30 45 60 P(A' = x) | 0.24 0.46 0.13 0.11 0.06 * Part B: Find die variance. * E A" =x 1 p + x 2 p 2 + x 2 pt = 0(0.24) + 15(0.46) + 30(0.13) + 45(0.11) + 60(0.06) = 19.35 = p Vor A =p. x x —p) 2 -pj.x 2 - p ' + p ; x 3 “ p ? = 0.24(0 - 19.35) 2 + 0.46(15 - 19.35) 2 + 0.13(30 - 19.35) 2 + 0.11(45 - 19.35) 2 + 0.06(60 - 19.35) 2 = 284.8275

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    2 Q3. The choices for problem number 12 part c, from Section 7 3 in the book are given below. * A. 5.4866 ' B. 7.4532 * C. 4.5727 ' D. 5.0197 * E. 6.8147 * F. None of the above. * x I -6 -1 ___ 0 8 P(X = x) | 0.21 0.25 0.26 0.28 * Part C: Find die standard deviation. * Standard deviation = o = V Var (X J * E(X) = -6(0.21) + (-1X0.25) + 0(0.26) + 8(0.28) = 0.73 = p * Vai(X) = 0.21(-6 - 0.73) 2 - 0.25( 1 - 0.73) 2 + 0.26(0 - 0.73) 2 + 0.28(8 - 0.73) 3 = 25.1971 * o = <25.1971 « 5.0197 * 5.0197 Q4. The choices for problem number 20 part c, from Section 7.3 in the book are given below. * A. 0.9897 * B. 0.7940 * C. 1.0135 * D. 0.9236 * E. 0.8688 * F. None of the above. • * The table below gives the number of days it takes for packages to be delivered from an online retailer and the probability associated with each number of days. * Number of Days | 3 4 5 6 7 Probability | 0.01 0.14 0.46 0.25 0.14 * Part C: Find the standard deviation of the random variable. * Standard deviation = o = V Vor (x ) * E(X) = 3(0.01) + 4(0.14) + 5(0.46) + 6(0.25) + 7(0.14) = 5.37 = p ' Var(X) = 0.01(3 - 5.37) 2 + 0.14(4 - 5.37) 2 + 0.46(5 - 5.37) 2 + 0.25(6 - 5.37) 2 + 0.14(7 - 5.37) 2 = 0.8531 * cr = <0.8531 a 0.9236 * 0.9236

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    3 Qz>. The choices for problem number 26 pan a, from Section 7.3 in the book are given below. * A. 6 * B. 0.9722 * C. 0.8333 * D. 0.5556 * E. 0.4444 * F. None of the above. A probability distribution has a mean of 12 and a standard deviation of . Use Chebyshev's inequality to approximate the probability that an outcome of the experiment lies between: p = 12, o = 7 Pan A: P(10 < x < 14) solve for k p - ko = small | p - ko = Big 12 “k 1 ; =10 | 12 + k j =14 ~1 1 / k = - 2 1 3 3 k = 6 | k = 6 1 1 1 I ’ T -1 = 1- — = 1 - RJ 0.9722 k 2 6 s 0.9722 Q6. The choices for problem number 26 pan b, from Section 7.3 in the book are given below. * A. 12 * B. 0.9167 * C. 0.4375 * D. 0.9931 * E. 0.5625 * F. None of the above. * A probability distribution has a mean of 12 and a standard deviation of . Use Chebyshev's inequality to approximate the probability that an outcome of the experiment lies between: 1 * p = 1 2 , o = 3 Pan B: P(8 < x < 16) solve for k * p - ko = small | p - ko = Big 12— k ’ i - S I 12 + k 1 1 = 1 6 3 1 3 | l k = 4 k = 12 | k = 12 =1 -lb = 1- -fh Rs 0.9931 144 ----- * 0.9931

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