Solution Of System Of Equations Using Matrix Method: A Step-By-Step Approach
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Solution of System of Equations Using Matrix Method: A Step - by - Step Approach Question Solve the following system of equations using matrix method: π π + π π + ππ π = π , π π β π π + π π = π , π π + π π β ππ π = π Topic: Matrix Sub Topic: Solution of system of equations by matrix method CLASS - XII Solution: Step - 1 β Let us assume that: 1 π₯ = π , 1 π¦ = π and 1 π§ = π , the system takes the form: 2 π + 3 π + 10 π = 4 β¦β¦β¦β¦β¦β¦β¦ (1) 4 π β 6 π + 5 π = 1 β¦β¦β¦β¦β¦β¦β¦β¦ (2) 6 π + 9 π β 20 π = 2 β¦β¦β¦β¦β¦β¦β¦. (3) Step - 2 - Matrix equation and notations The above system is given by the matrix equation: AX = B OR X = π¨ β π π© Where A = [ 2 3 10 4 β 6 5 6 9 β 20 ] 3 π 3 , B = [ 4 1 2 ] 3 π 1 , X = [ π π π ] 3 π 1 Step - 3 - Determinant of A | π΄ | = | 2 3 10 4 β 6 5 6 9 β 20 | = 1200 β 0 β System has a unique solution and hence consistent. Step - 4 - Cofactors π΄ 11 = 75 , π΄ 12 = 110 , π΄ 13 = 72 π΄ 21 = 150 , π΄ 22 = β 100 , π΄ 23 = 0 π΄ 31 = 75 , π΄ 32 = 30 , π΄ 33 = β 24 Step - 5 - Adjoint of A
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