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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Document preview page 1

Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 1

Document preview content for Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition

Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition

Boost your textbook learning with Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition, providing the answers and solutions you need to succeed.

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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 1 preview image11–1.Evaluate each of the following and express with anappropriate prefix: (a) (430 kg)2, (b) (0.002 mg)2, and(c) (230 m)3.Solutiona)(430 kg)2=0.185(106) kg2=0.185 Mg2Ans.b)(0.002 mg)2=[2(10-6) g]2=4mg2Ans.c)(230 m)3=[0.23(10 ) m]33=0.0122 km3Ans.Ans:0.185 Mg24mg20.0122 km3
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 2 preview image
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 3 preview image21–2.Represent each of the following combinations of units in thecorrect SI form: (a) Mg>ms, (b) N>mm, (c) mN>(kg#ms).Solution(a)Mgms=103kg10-3s=106kg>s=Gg>sAns.(b)Nmm=1 N10-3m=103N>m=kN>mAns.(c)mN(kg#ms)=10-3N10-6kg#s=kN>(kg#s)Ans.Ans:Gg>skN>mkN>(kg#s)
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 4 preview image31–3.What is the weight in newtons of an object that has a massof (a) 8 kg, (b) 0.04 kg, and (c) 760 Mg?Solution(a)W=9.81(8)=78.5 NAns.(b)W=9.81(0.04)(10-3)=3.92(10-4) N=0.392 mNAns.(c)W=9.81(760)(103)=7.46(106) N=7.46 MNAns.Ans:W=78.5 NW=0.392 mNW=7.46 MN
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 5 preview image4Represent each of the following combinations of units inthecorrectSIform:(a)>ms,(b)>mN,and(c)MN>(kg#ms).Solution(a)kN>ms=103N>(10-6)s=GN>sAns.(b)Mg>mN=10 g6>-3=Gg>NAns.(c)MN>(kg#ms)=106N>kg(10-3=GN>(kgs)#Ans.*1–4.(10)N)sKNMgAns:GN>sGg>NGN>(kg#s)
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 6 preview image51–5.Represent each of the following quantities in the correctSI form using an appropriate prefix: (a) 0.000 431 kg,(b), and (c) 0.005 32 km.35.3(103) NSOLUTIONa)Ans.b)Ans.c)Ans.0.005 32 km=0.005 32A103Bm=5.32 m35.3A103BN=35.3 kN0.000 431 kg=0.000 431A103Bg=0.431 gAns:0.431g35.3kN5.32m
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 7 preview image61–6.SOLUTIONa)Ans.b)Ans.c)Ans.d) kmAns.#mN=103m10-6N=10-3m=mmks>mg=11023s1102-6kg=11029skg=Gs>kgmkm=1102-611023m=1102-3m=mmm>ms=¢m1102-3s≤=¢11023ms≤=km>sRepresent each of the following combinations of units inthe correct SI form using an appropriate prefix: (a)(b)(c) ksand (d) km#mN.mkm,#N#N>mg,m>ms,Ans:km>smmGs>kgmm#N
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 8 preview image71–7.Represent each of the following as a number between 0.1and1000usinganappropriateprefix:(a)45 320kN,(b)568(105) mm, and (c)0.00563 mg.Solution(a)45 320 kN=45.3 MNAns.(b)568(105) mm=56.8 kmAns.(c)0.00563 mg=5.63mgAns.Ans:45.3 MN56.8 km5.63mg
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 9 preview image8Represent each of the following combinations of units in thecorrect SI form: (a)GN#mm,(b)kg>mm,(c)N>ks , and2(d)KN>ms.Solution(a)GN#mm=109(10-6) N#m=kN#mAns.(b)kg>mm=103g>10-6m=Gg>mAns.(c)N>ks2=N>106s2=10-6N>s2=mN>s2Ans.(d)kN>ms=103N>10-6s=109N>s=GN>sAns.*1–8.Ans:kN#mGg>mmN>s2GN>s
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 10 preview image91–9.SOLUTIONa)Ans.b)Ans.c)Ans.=mm#kgmmMg#=C10-6mD#C103kgD=(10)-3m#kgmN>ms=10-3N10-6s=103Ns=kN>sMg>mm=103kg10-3m=106kgm=Gg>mRepresent eachof the following combinations of unitsinthe correct SI form using an appropriate prefix: (a) Mg/mm,(b)(c)mm#Mg.mN>ms,Ans:Gg>mkN>smm#kg
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 11 preview image101–10.Represent eachof the following withSI unitshaving anappropriate prefix: (a) 8653 ms, (b) 8368 N, (c) 0.893 kg.SOLUTIONa)Ans.b)Ans.c)Ans.0.893 kg=893(10-3)(103) g=893 g8368 N=8.368 kN8653 ms=8.653(10)3(10-3) s=8.653 sAns:8.653 s8.368kN893g
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 12 preview image111–11.Using the SI system of units, show that Eq. 1–2 is adimensionally homogeneous equation which givesFinnewtons.Determinetothreesignificantfiguresthegravitational force acting between two spheres that aretouching each other. The mass of each sphere is 200 kg andthe radius is 300 mm.Ans:7.41mNSOLUTIONUsing Eq. 1–2,Ans.=7.41A10-6BN=7.41mN=66.73A10-12B c200(200)0.62dF=G m1m2r2N=am3kg#s2b akg#kgm2b=kg#ms2(Q.E.D.)F=G m1m2r2
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 13 preview image12Roundoffthefollowingnumberstothreesignificantfigures: (a) 58 342 m, (b) 68.534 s, (c) 2553 N, and(d) 7555 kg.SOLUTIONa)58.3 kmb)68.5 sc)2.55 kNd)Ans.7.56 Mg*1–12.Ans:58.3km68.5s2.55kN7.56Mg
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 14 preview image131–13.A rocket has a mass of 3.529(10 ) kg on earth. Specify(a) its mass in SI units and (b) its weight in SI units. If therocket is on the moon, where the acceleration due to gravityisgm=1.61 m/s2,determine to three significant figures(c) its weight in SI units and (d) its mass in SI units.Solutiona)3.529(106) kg=3.53 GgAns.b)We=mg=33.52911062kg4 19.81 m>s22=34.61911062kg#m>s2=34.6 MNAns.c)Wm=mgm=33.52911062kg4 11.61 m>s22=5.68211062N=5.68 MNAns.OrWm=Weagmgb=(34.619 MN)a1.61 m>s29.81 m>s2b=5.68 MNd) Since the mass is independent of tis location, thenmm=me=3.53 GgAns.Ans:3.53 Gg34.6 MN5.68 MNmm=me=3.53 Gg6
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 15 preview image141–14.and (c) 435 MN 23.2 mm.>(a) 354 mg(45 km)(0.0356 kN), (b) (0.004 53 Mg) (201 ms),>SOLUTIONa)Ans.b)Ans.c)Ans.435 MN>23.2 mm=435A106BN23.2A10-3Bm=18.75A109BNm=18.8 GN>m=0.911 kg#s(0.00453 Mg)(201 ms)=C4.53A10-3B A103BkgD C201A10-3BsD=0.447 kg#m>N=0.447A103Bg#mN(354 mg)(45 km)>(0.0356 kN)=C354A10-3BgD C45A103BmD0.0356A103BNEvaluate each of the following to three significant figures andexpress each answer in Sl units using an appropriate prefix:Ans:0.447 kg#m>N0.911 kg#s18.8 GN>m
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Solution Manual for Engineering Mechanics Statics in SI Units, 14th Edition - Page 16 preview image151–15.Evaluate each of the following to three significant figures andexpress each answer in SI units using an appropriate prefix:(a)(212 mN) , (b)2(52 800Solution(a)(212 mN)2=3212(10)-3N42=0.0449 N2=44.9(10)-3N2Ans.(b)(52 800 ms)2=352 800(10)-342s2=2788 s2=2.79(103) s2Ans.(c)3548(10)6412ms=(23 409)(10)-3s=23.4(10)3(10)-3s=23.4 sAns.Ans:44.9(10)-3N22.79(103) s223.4 sms) , and (c)2[548(10 )]61>2ms.
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Mechanical Engineering
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Engineering Mechanics: Statics Dyna...

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