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Solution Manual for Fundamentals of Momentum, Heat and Mass Transfer, 6th Edition

Solution Manual for Fundamentals of Momentum, Heat and Mass Transfer, 6th Edition is the key to mastering your textbook, offering easy solutions and clear explanations.

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    Chapter 1 End of Chapter Problem Solutions 1.1 n = 4 x 10 20 molecules/in 3 = = 1.32x10 4 in./s A= (10 -3 in) 2 NA = n A=1.04x10 8 m/s

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    1.2 Flow Properties: Velocity, Pressure Gradient, Stress Fluid Properties: Pressure, Temperature, Density, Speed of Sound, Specific Heat

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    1.3 mass of solid= ρ s v s mass of fluid= ρ f v f mix = = =

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    1.4 Given = 7 For P 1 = 1 atm = 1.01 P= 3001(1.01) 7 – 3000 = 217 atm

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    1.5 At Constant Temperature = constant = constant For 10% increase in P must also increase by 10 %

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    1.6 Since density varies as & =nM (M=Molecular wt.) n 250,000 = n S.L. = 4 x 10 20 = 2.5 x 10 16

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    1.7 = x + y = + = x + y = + Q.E.D.

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    1.8 = + = = = Q.E.D.

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    1.9 Transformation from (x,y) to (r, ) = + = + r 2 = x 2 +y 2 = so: = = = = = = = = = = +

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    1.10 = + + = ( ) + ( + ) + = ( + ) + ( + ) + Thus: = +

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    1.11 P= + P(a,b)= 2 + (sin1cos1) = 2 {[ + 2) + ( )

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    1.12 T(x,y)= T o e -1/4 [ (cos cosh ) + (sin sinh ) T(a,b)= T o e -1/4 [ (cos cosh1) + (sin sinh1) = T o e -1/4 [ + ] = [ (1+e -2 ) +

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    1.13 In problem 1.12 T(x,y) is dimensionally homogeneous (D.H.) P(x,y) in Prob 1.11 will be D.H. if ~ L Bf s 2 / ft 4 or using the conversion factor g c

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    1.14 = 3x 2 y+4y 2 A scalar field is given by the function: (a) Find at the point (3,5) For the value of at the point (3,5) (b) Find the component of that makes a -60 angle with the axis at the point (3,5) Let the unit vector be represented by At the point (3,5) this becomes:

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    1.15 For an ideal gas P= From Prob 1.3 :

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