Analysis of Standard Deviation, Data Spread, and Outliers in Data Sets1. a) Create a set of 5 points that are very close together and record the standard deviation. Next,add a 6th point that is far away from the original 5 and record the newstandard deviation.What is the impact of the new point on the standard deviation? Do not just give a numericalvalue for the change. Explain what happened to the standard deviation in words. (4 points)The standard deviation of the 5 values those are very close together is obtained as 2.92.If we add the value 75 that is far away from initial set of 5 numbers. Now the standarddeviation to the set of 6 numbers is 20.98.Preview Mode
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