Application of Gas Laws in Various Thermodynamic Processes1.Given an isothermal process where P1=2.5 mmHgP_1 = 2.5\,\text{mm Hg}P1=2.5mmHg,V1=3.5 LV_1 = 3.5\,\text{L}V1=3.5L, and P2=10 mmHgP_2 = 10\,\text{mm Hg}P2=10mmHg,what is thefinal volume V2V_2V2after the pressure changes?Answer:1.𝐴𝑠𝑤𝑒𝑘𝑛𝑜𝑤𝑓𝑜𝑟𝑡ℎ𝑒𝑖𝑠𝑜𝑡ℎ𝑒𝑟𝑚𝑖𝑐𝑝𝑟𝑜𝑐𝑒𝑠𝑠𝑃𝑉=𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡𝑠𝑜𝑃1𝑉1=𝑃2𝑉2(3.5𝐿)(2.5𝑚𝑚𝐻𝑔)=𝑉2(10𝑚𝑚𝐻𝑔)𝑠𝑜𝑉2=(3.5𝐿)(2.5𝑚𝑚𝐻𝑔)10𝑚𝑚𝐻𝑔=0.875𝐿2.In a process where the volume is constant, the relationship between pressure and temperatureis given by P∝TP\propto TP∝T. Given that P1=4.1 atmP_1 = 4.1\,\text{atm}P1=4.1atm,T1=100∘CT_1 = 100^\circ CT1=100∘C, and T2=185∘CT_2 = 185^\circ CT2=185∘C, calculate thefinal pressure P2P_2P2.Answer:2.𝑆𝑖𝑛𝑐𝑒𝑡ℎ𝑒𝑣𝑜𝑙𝑢𝑚𝑒𝑖𝑠𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡𝑠𝑜𝑓𝑜𝑟𝑡ℎ𝑖𝑠𝑝𝑟𝑜𝑐𝑒𝑠𝑠𝑃∝𝑇ℎ𝑒𝑛𝑐𝑒𝑃1𝑇1=𝑃2𝑇2𝑇1=100℃=100+273=373𝐾𝑇2=185℃=185+273=478𝐾𝑃1=4.1𝑎𝑡𝑚4.1373=𝑃2478𝑃2=5.254𝑎𝑡𝑚3.Given that the pressure is constant, use Charles' Law to calculate the final temperature T2T_2T2.Given:•Initial volume V1=25 LV_1 = 25\,\text{L}V1=25L•Initial temperature T1=10∘CT_1 = 10^\circ CT1=10∘C•Final volume V2=50 LV_2 = 50\,\text{L}V2=50LAnswer:Preview Mode
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