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Stoichiometric Calculations And Gas Volume Determinations In Chemical Reactions

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    Stoichiometric Calculations and Gas Volume Determinations in Chemical Reactions 1) The balanced equation is : 𝐿𝑖𝑂𝐻 + π»π΅π‘Ÿ β†’ πΏπ‘–π΅π‘Ÿ + 𝐻 2 𝑂 We have : n(LiOH) used = n(LiBr) produced = m(LiOH)/M(LiOH) = 10 6 . 941 + 15 . 9994 + 1 . 00794 = 0 . 418 π‘šπ‘œπ‘™ Then m(LiBr) = M(LiBr) * n(LiBr) = (6.941+79.904)*0.418 = 36.3 g 2) The balanced equation is : 𝐢 2 𝐻 4 + 3 𝑂 2 β†’ 2 𝐢𝑂 2 + 2 𝐻 2 𝑂 We have : n( C2H4 ) used = n(CO2 ) produced /2 then n(CO2) produced = 2 βˆ— 45 4 βˆ— 1 . 00794 + 2 βˆ— 12 . 0107 = 3 . 208 π‘šπ‘œπ‘™ then m(CO2) = M(CO2) * n(CO2) = (12.0107+2*15.9994)*3.208 = 141.2 g 3) The balanced equation is : 𝑀𝑔 + 2 π‘π‘ŽπΉ β†’ 𝑀𝑔 𝐹 2 + 2 π‘π‘Ž We have : n(Mg) used = n(Na) produced /2 then n(Na) produced = 2 βˆ— 5 . 5 24 . 305 = 0 . 453 π‘šπ‘œπ‘™ Therefore m(Na) = M(Na) * n(Na) = 22.989770 * 0.453 = 10.4 g 4) The balanced equation is : 2 𝐻𝐢𝑙 + π‘π‘Ž 2 𝑆𝑂 4 β†’ 2 π‘π‘ŽπΆπ‘™ + 𝐻 2 𝑆𝑂 4 We have : n( HCl ) used /2 = n( H2SO4 ) produced = 20 2 βˆ— ( 1 . 00794 + 35 . 453 ) = 0 . 274 π‘šπ‘œπ‘™ then m(H2SO4) = M(H2SO4) * n(H2SO4) = (2*1.00794 + 32.066 + 4*15.9994)*0.274 = 26.9 g 1) The balanced equation is : 𝑀𝑔 + 2 𝐻𝐢𝑙 β†’ 𝐻 2 + 𝑀𝑔 𝐢𝑙 2 We have : n(Mg) used = n(H2) produced = 20 24 . 305 = 0 . 823 π‘šπ‘œπ‘™ Then the number of liters of H2 gas produced is : 0.823 * 22.4 = 18.4 L 2) The balanced equation is : 2 𝐾𝐢𝑙 𝑂 3 β†’ 3 𝑂 2 + 2 𝐾𝐢𝑙 We have : n(KClO3) used /2 = n(O2) produced /3 then n(O2) produced = 3 2 βˆ— 7 . 5 = 11 . 25 π‘šπ‘œπ‘™ Then the number of liters of H2 gas produced is : 11.25 * 22.4 = 252 L 3) The balanced equation is : 2 π‘π‘ŽπΌ + 𝐢𝑙 2 β†’ 2 π‘π‘ŽπΆπ‘™ + 𝐼 2 We have : n(Cl2) used = n(NaCl) produced /2 then n(NaCl) produced = 2 βˆ— 𝑛 ( 𝐢𝑙 2 ) = 2 βˆ— 45 . 3 22 . 4 = 4 . 04 π‘šπ‘œπ‘™ 4) The balanced equation is : 2 𝐾 + 2 𝐻 2 𝑂 β†’ 2 𝐾𝑂𝐻 + 𝐻 2 We have : n(K) used /2 = n(H2) produced then n(K) us ed = 𝑛 ( 𝐻 2 ) 2 = ( 35 . 6 22 . 4 ) 2 = 0 . 795 π‘šπ‘œπ‘™ Then m(K) = M(K) * n(K) = 39.0983 * 0.795 = 31.1 g

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