BIOD210 Anatomy and Physiology Final Exam With Answers (23 Solved Questions)

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BIOD 210Final ExamRequiresRespondusLockDown Browser + Webcam●DueNo due date●Points140●Questions23●Time Limit90 Minutes●Requires Respondus LockDown BrowserAttempt HistoryAttempt Time ScoreLATESTAttempt151minutes140

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Question 1Not yet graded / 5 ptsList two organs contained in the abdominal cavity.Your Answer:the the stomach and thespleenThe abdominal cavity contains the stomach, intestines, spleen and liverQuestion 2Not yet graded / 5 ptsTrue or False?a.The purpose of cellular respiration is to produce ADP. (T or F)

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b.Peripheral proteins are found on the outer surface of a cell membrane. (T or F)c.Exocytosis is the process that occurs to bring biomacromolecules inside the cell.(T orF)d.Receptor-mediated endocytosis uses a signaling molecule from another cell,binding to the cell membrane to bring about changes within the cell proteins. (Tor F)e.Endocytosis is a passive process. It does not require cellular energyexpenditure.(T or F)Your Answer:a.False. ATPb.Truec.Falsed.True

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e.Falsea.False- (ATP is produced, not ADP)b.Truec.False- (This process is called endocytosis)d.Truee.False- (Endocytosis is an active process and requires cellular energy)Question 3Not yet graded / 5 ptsNote: Essay answers must clearly be in your own words.In your own words, discuss Tay-Sachs disease. What organelle within the cell isimpacted? What are the symptoms of the disease and why do they occur?

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Your Answer:Tay-Sachs occurs when a digestive enzyme in lysosomes is missing. Since thedigestive enzyme is missing, toxic lipids build up inside the cell which can lead tomental disability and death.(1) Lysosomes(2)buildup of toxic lipids inside the cell (biomacromolecules )(3)disability and deathIn the genetic disease known as Tay-Sachs, one of the normally presentdigestive enzymes inside lysosomes is lacking. Thus, a toxic lipid in thebrain cells cannot be broken down. The resulting buildup of lipids inthese cells can cause intellectual disability and death.Question 4Not yet graded / 5 ptsNote: Essay answers must clearly be in your own words.You are observing two cells under the microscope. They are the same type ofeukaryotic cell but one appears much larger. Based on appearance alone, which

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one would you expect to be carrying out respiration at a more active rate, thelarger or smaller cell? Explain why.Your Answer:The smaller cell because as a cell grows larger the ratio of the surface area tovolume decreases. The smaller cell is able carry out respiration faster becauserelative to the larger cell it has a larger surface area compared to its volume andcan carry out respiration faster.The smaller cell. Cells need to remain relatively small because as a cellexpands the amount of surface area relative to the volume of the celldecreases. The smaller cell is more active because relative to its volume,its surface area is larger than a bigger cell. With a larger surface area(relative to its volume) this allows the metabolic processes to occurfaster.Question 5Not yet graded / 5 ptsNote: Essay answers must clearly be in your own words.Explain what happens to the soft palate during swallowing. Why?Your Answer:

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During swallowing the soft palate moves upward to prevent food and liquid fromentering the nasal passages.The upward movement of the soft palate prevents food or liquid fromentering the nasal passages during swallowing.Question 63 / 3 ptsAir and food pass in which one of the following areas:TracheaNasopharynxCorrect!OropharynxAlveoliQuestion 7Not yet graded / 10 pts

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Label the following five items from the diagram:Label A- __________Label C- __________Label E- __________

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Label F- __________ Label H- __________Your Answer:Label A- Nasal CavityLabel C- Soft PalateLabel E- GlottisLabel F- tracheaLabel H- TongueLabel A- Nasal CavityLabel C- Soft Palate/ UvulaLabel E- GlottisLabel F- TracheaLabel H- Tongue

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