CramX Logo
Analysis of Risk and Probability Distributions in Insurance and Inventory Management - Document preview page 1

Analysis of Risk and Probability Distributions in Insurance and Inventory Management - Page 1

Document preview content for Analysis of Risk and Probability Distributions in Insurance and Inventory Management

Analysis of Risk and Probability Distributions in Insurance and Inventory Management

A detailed analysis of risk and probability distributions in insurance and inventory management.

Evelyn Morris
Contributor
4.7
0
12 months ago
Preview (3 of 7 Pages)
100%
Log in to unlock
Page 1 of 3
Analysis of Risk and Probability Distributions in Insurance and Inventory Management - Page 1 preview imageAnalysis of Risk and Probability Distributions in Insurance and InventoryManagementBuffalo is analyzing inventory risk from potential fires at its warehouse and considering twooptions: Option A, where all inventory is stored in onewarehouse, and Option B, where theinventory is split into two warehouses. For both options, calculate the expected loss, variance,and standard deviation. Determine which option carries more risk using these metrics andexplain the significance of the coefficient of variation in measuring this risk. Additionally,discuss how pooling both warehouses into a single insurance policy would affect the risk andpremium, referencing the Law of Large Numbers.Word Count Requirement: 700-1000 words.
Page 2 of 3
Analysis of Risk and Probability Distributions in Insurance and Inventory Management - Page 2 preview image
Page 3 of 3
Analysis of Risk and Probability Distributions in Insurance and Inventory Management - Page 3 preview imageRMI 2101 SUGGESTEDANSWERS TO HOMEWORK NUMBER FIVENOT ONLY POSSIBLE METHODSSEEALSO COMMENTS ON YOUR HWPAPERS1.CIVIL AIR PATROL. TWO REGIONS. PANE AND PASW.# of Accidents per airplaneP of having this # of accidents0.601.252.103.05SUM = 1.00A.RANDOM VARIABLE IS A VARIABLE WHOSE OUTOCME OR VALUEDEPENDS UPON SOME CHANCE EVENTSRANDOM VARIABE HERE IS THE EXPECTED # OF ACCIDENTS PERAIRPLANEPER YEAR.B.P OF HAVING THREE LOSSES = .05.THE SUM OF ALL OF THEPOSSIBLE OUTCOMESFOR A DISCRETE EMPIRICALPROBABILITY DISTRIBUTIONMUST = 1.00.1.00-.95(P OF A LOSS < 3)= .05C.P* EXPECTED NUMBER OF ACCIDENTS PER AIRPLANE PER YEARFOR THE NE = P*FREQUENCY = 0 (.6) + 1(.25) + 2 (.10) +3 (.05)= 0 + .25+ .20 + .15 = .60P* = .60 NUMBER OF ACCIDENTS PER AIRPLANE PER YEAR INTHENEREGION.UNITOF MEASUREMENT ISTHEFREQUENCY OF,OR # OFACCIDENTS(PER AIRPLANE PER YEAR).D.500PLANES IN THE NE REGION.P*NUMBER OF ACCIDENTS FORALLPLANES INTHE NE REGION=500X.60 = 300
Preview Mode

This document has 7 pages. Sign in to access the full document!