Analysis of Variance and t-Test Comparison in Evaluating Teaching Methods

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Analysis of Variance and t - Test Comparison in Evaluating Teaching Methods 1. When only two treatments are involved, ANOVA and the Student t test (Chapter 11) result in the same conclusions. Also, t 2 = F. As an example, suppose that 14 randomly selected students were divided into two groups, one consisting of 6 students and the other of 8. One group was taught using a combination of lecture and programmed instruction, the other using a combination of lecture and television. At the end of the course, each group was given a 50 - item test. The following is a list of the number correct for each of the two groups. Using analysis of variance techniques, test the null hypothesis, H 0 that the two mean test scores are equal. Lecture and Programmed Instruction Lecture and Television 12 37 15 23 26 33 22 24 12 27 13 29 25 25 a. Complete the ANOVA table (2 decimal places) Source SS df MS F Factor 430.72 1 430.72 15.10 Error 342.21 12 28.52 Total 772.93 13 b. Using a σ = 0.1 level of significance, compute the test statistic F:
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