ANOVA Analysis of Temporary Employee Work Duration Across Different Industries

Preview (3 of 8 Pages)

100%

ANOVA Analysis of Temporary Employee Work Duration Across Different Industries - Page 1 preview image

Loading page ...

ANOVA TestingThe manager of an agency providing temporary employees to city offices is analyzing thenumber of days temporary hires typically work in various types of industries.The data are as follows:a.Legal clerical: 2, 1, 4, 4, 2, 5, 6b.Accounting firms: 3, 6, 4, 5, 5, 7, 8c.Insurance: 5, 4, 7, 9, 9, 8, 11Using the data above, answer the following questions:Are there significant differences in the length of time temporary employee’s work in thedifferent industries?How much of the differences can be explained by the industry?Which groups are significantly different from others?Why would a manager be focused on measuring the number of days that a temporary works eachweek?SUMMARY FOR SINGLEFACTORSINDUSTRYTYPESTOTALSUMMEANVARIANCELegal Clerical7243.4285714293.2857AccountingFirms7385.4285714292.9524Insurance7537.5714285715.9524Legal Clerical2-3.428571429=-1.428571429(-1.428571429 x-1.428571429)=2.0401-3.428571429=-2.428571429(-2.428571429 x-2.428571429)=5.8974-3.428571429=0.571428571(0.571428571 x 0.571428571)=0.3264-3.428571429=0.571428571(0.571428571 x 0.571428571)=0.3262-3.428571429=-1.428571429(-1.428571429 x-1.428571429)=2.0405-3.428571429=1.571428571(1.571428571 x 1.571428571)=2.4696-3.428571429=2.571428571(2.571428571 x 2.571428571)=6.61219.71

ANOVA Analysis of Temporary Employee Work Duration Across Different Industries - Page 2 preview image

Loading page ...

ANOVA Analysis of Temporary Employee Work Duration Across Different Industries - Page 3 preview image

Loading page ...

Variances2=Σ(x−M)2n−1S2 = 19.91728571/6S2 = 3.2857Accounting Firms3-5.428571429=-2.428571429(-2.428571429 x-2.428571429)=5.8976-5.428571429=0.571428571(0.571428571 x 0.571428571)=0.3264-5.428571429=-1.428571429(-1.428571429 x-1.428571429)=2.0405-5.428571429=-0.428571429(-0.428571429 x-0.428571429)=0.185-5.428571429=-0.428571429(-0.428571429 x-0.428571429)=0.187-5.428571429=1.571428571(1.571428571 x 1.571428571)=2.4698-5.428571429=2.571428571(2.571428571 x 2.571428571)=6.61217.71Variances2=Σ(x−M)2n−1s2 = 17.71428571/6s2 = 2.9524Insurance5-7.571428571=-2.571428571(-2.571428571 x-2.571428571)=6.6124-7.571428571=-3.571428571(-3.571428571 x-3.571428571)=12.757-7.571428571=-0.571428571(-0.571428571 x-0.571428571)=0.3269-7.571428571=1.428571429(1.428571429 x 1.428571429)=2.0409-7.571428571=1.428571429(1.428571429 x 1.428571429)=2.0408-7.571428571=0.428571429(0.428571429 x 0.428571429)=0.1811-7.571428571=3.428571429(3.428571429 x 3.428571429)=11.7535.71Variances2=Σ(x−M)2n−1

Preview Mode

This document has 8 pages. Sign in to access the full document!

Report

Study Now!

Document Details

Related Documents

Statistics - Univariate Inferential Tests

Statistics - Sampling

Statistics - Probability

Statistics - Principles of Testing

Statistics - Numerical Measures

Statistics - Introduction to Statistics

Statistics - Graphic Displays

Statistics - Cummulative Reviews

Statistics - Common Mistakes and Tables

Statistics - Bivariate Relationships

Company

Explore

Study Tools