CramX Logo
Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Document preview page 1

Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Page 1

Document preview content for Comprehensive Statistical Analysis: Descriptive Statistics, Probability

Comprehensive Statistical Analysis: Descriptive Statistics, Probability

A solved exam on comprehensive statistical methods, covering descriptive statistics, hypothesis testing, regression, and confidence intervals.

Benjamin Clark
Contributor
4.3
0
12 months ago
Preview (4 of 11 Pages)
100%
Log in to unlock
Page 1 of 4
Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Page 1 preview imageComprehensive Statistical Analysis: Descriptive Statistics, Probability,Hypothesis Testing, Regression, and Confidence IntervalsAnswer all 30 questions. Make sure your answers are as complete as possible. Show all of yourwork and reasoning. In particular, when there are calculations involved, you must show how youcame up with your answers with critical work and/or necessary tables. Answers that come straightfrom programs or software packages will not be accepted.Refer to the following table for Questions 1, 2, and 3.The table shows temperatures on the first 12 days of October in a small town in Maryland.DateTemperatureDateTemperatureDateTemperatureOct 173Oct 553Oct 962Oct 266Oct 653Oct 1049Oct 366Oct 762Oct 1152Oct 470Oct 855Oct 12571.Determine the five number summary for this data.Put your numbers in order.49, 52, 53, 53, 55, 57, 62, 62, 66, 66, 70, 73Find the minimum and maximum.The minimum is 49 and the maximum is 73Find the medianGiven d7ata is even, take average of two middle valuesMedian=5.59211926257==+Place parentheses around the numbers above and below the median.49, 52,53, 53, 55,57, 62, 62, 66,66, 70, 73Q1=53Q3=66Write down your five number summaryminimum=1,Q1 =53, median=59.5,Q3=66, and maximum=737.2.Determine the mean temperature.8.591271812737066666262575553535249==+++++++++++=Mean3.Determine the mode(s), if any.
Page 2 of 4
Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Page 2 preview image
Page 3 of 4
Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Page 3 preview imageThere are 3 modes in this data, 53, 62, 66Refer to the following situation for Questions 4, 5, and 6.Consider the following distribution by age groups.AgeFrequencyRelative Frequency10140.0415-192024102529630345353944044245491Total504.Complete the table.AgeFrequencyRelativeFrequency10140.04*50=20.0415-190.40*50=201-0.60*=0.402024100.20252960.12303450.10353940.08404420.04454910.02Total50*0.04+0.20+0.12+0.10+0.08+0.04+0.02=0.605.Is the distribution bell-shaped, skewed to the left, or skewed to the right? Explain your answer.
Page 4 of 4
Comprehensive Statistical Analysis: Descriptive Statistics, Probability - Page 4 preview image00.050.10.150.20.250.30.350.40.4512345678Relative FrequencySkewed to the right: The right tail of the histogram is longer than the left tail.6.In what age range is the median? Explain your answer.AgeFrequencyClassBoundaryCumulativeFrequency101429.5-14.5215-192014.5-19.52220241019.5-24.5322529624.5-29.5383034529.5-34.5433539434.5-39.5474044239.5-44.5494549144.5-49.550Total50itemitemncnfhlMedianthth2525022==+=7.Your entire gold coin collection consists of 5 coins. Their weights are 2, 3, 8, 7, and 6 ouncesrespectively. Find the standard deviation of their weights. Show all work.Mean = (2+3+8+7+6) / 5 = 26/5 = 5.2s² = [(2-5.2)² + (3-5.2)² + (8-5.2)² + (7-5.2)² + (6-5.2)²] / (5-1)
Preview Mode

This document has 11 pages. Sign in to access the full document!