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Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA - Document preview page 1

Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA - Page 1

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Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA

This document provides a solved statistical analysis using t-tests and ANOVA to compare creativity and blood pressure data.

Lily Green
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Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA - Page 1 preview imageStatistical Analysis of Creativity and Blood Pressure Measurements: AComparative Study Using t-tests and ANOVAPart A. Dependent t testFor this assignment, we are interested in finding out whether participation in a creativewriting courseresults in increased scores of a creativity assessment. For this part of theactivity, you will be using the data file “Activity 4a.sav”. In this file, “Participant” is thenumeric student identifier, “CreativityPre” contains creativity pre-test scores, and“CreativityPost” contains creativity post-test scores. A total of 40 students completed thepre-test, took the creativity course, and then took the post-test.1.Exploratory Data Analysis/Hypothesesa.Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS,calculate the mean and standard deviation of these two variables.b.Construct an appropriate chart/graph that displays the relevant information forthese two variables.c.Write the null and alternative hypotheses used to test the question above (e.g.,whether participation in the course affects writing scores).2.Comparison of Meansa.Perform a dependent t test to assess your hypotheses above (note that manyversions of SPSS use the term “paired samples t test” rather than “dependent ttest”; the test itself is the same.b.In APA style, write one or two paragraphs that describe the dataset, gives yourhypothesis, and presents the results of the dependent sample t test.Answer:1>a , b & c)Here the null hypothesis H0: the participation in a creative writing courseresults is not increased in scores of creative assessment against thealternative H1: the participation in a creative writing course results isincreased in scores of creative assessment. In other words we can say thenull hypothesis H0: d=0 against the alternative hypothesis H1: d>0 where d ismean of the sample differences of the two sample.2>a &b)This is a paired sample t test. And the test statistics ist =Σ(differences of the observation)/((NΣ(differences of observation)2-(Σ(differences ofobservation))2)/ (N-1)). Where N is the sample size, here N=40.The SPSS result:Paired Samples StatisticsMeanNStd. DeviationStd. Error MeanPair 1Creativity pre-test40.15408.3041.313Creativity post-test43.35409.5981.518
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Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA - Page 2 preview image
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Statistical Analysis of Creativity and Blood Pressure Measurements: A Comparative Study Using t-tests and ANOVA - Page 3 preview imageThe means of Creativity pre-test is 40.15, standard deviation is 8.304 and the mean ofCreativity post-test is 43.35 and standard deviation is 9.598.Paired Samples CorrelationsNCorrelationSig.Pair 1Creativity pre-test &Creativity post-test40.650.000From the correlation matrix of these two variables we see that the correlation between them is0.650 and also from the scatter plot we observe that the correlation between them is high andthey are highlycorrelated.LowerUpperPair 1Creativitypre-test -Creativitypost-test-3.2007.5761.198-5.623-.777-2.67139.011Paired Samples TestPaired DifferencestdfSig. (2-tailed)MeanStd.DeviationStd. ErrorMean95% ConfidenceInterval of the
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