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Statistical Analysis of Hypothesis Testing and Comparative Studies - Document preview page 1

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Statistical Analysis of Hypothesis Testing and Comparative Studies

Exploration of hypothesis testing and comparative data analysis techniques.

Lily Green
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Statistical Analysis of Hypothesis Testing and Comparative Studies - Page 1 preview imageStatistical Analysis of Hypothesis Testing and Comparative Studies18. You choose an alpha level of .01 and then analyze your data.a. What is the probability that you will make a Type I error given that the nullhypothesis is true?The probability of type I error is actually alpha given that the null hypothesis is trueso it is 0.01.b. What is the probability that you will make a Type I error given that the nullhypothesis is false?When null hypothesis is false, it is impossible to make a type I error. It meansprobability that you will make a type I error given that the null hypothesis is false iszero.7. Below are data showing the results of six subjects on a memory test. The threescores per subject are their scores on three trials (a, b, and c) of a memory task.Are the subjects get-ting better each trial? Test the linear effect of trial for the data.abc467378285147469242
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Statistical Analysis of Hypothesis Testing and Comparative Studies - Page 3 preview imagea. Compute L for each subject using the contrastweights-1, 0, and 1. That is,compute (-1)(a) + (0)(b) + (1)(c) for each subject.L1-1*4+0*6+1*7=3L2-1*3+0*7+1*8=5L3-1*2+0*8+1*5=3L4-1*1+0*4+1*7=6L5-1*4+0*6+1*9=5L6-1*2+0*4+1*2=0b. Compute a one-sample t-test on this column (with the Lvalues for each subject)you created.M=Sample Mean = (3+5+3+6+5+0)/6 = 3.667Standard error of mean = Sm = 2.160/sqrt(6) = 0.8819t=(M-mu)/Sm = 3.667/0.8819 = 4.158Using calculator, we find out the probability of two tailed testto be 0.008813. You are conducting a study to see if students do better when they study all atonce or in intervals. One group of 12 participants took a test after studying for onehour continuously. The other group of 12 participants took a test after studying forthree twenty minute sessions. The first group had a mean score of 75 and avariance of 120. The second group had a mean score of 86 and a variance of 100.a. What is the calculated t value? Are the mean test scores of these two groupssignificantly different at the .05 level?n1 = 12 , x1 = 75 , s1 = 10.954n2 = 12 , x2 = 86 , s2 = 10
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